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Shalnov [3]
4 years ago
7

Which exponential function goes through the points (1, 16) and (4, 128)?

Mathematics
1 answer:
djyliett [7]4 years ago
7 0

Answer:

Here is the complete question (attachment).

The function which represent the given points are f(x)=8(2)^{x}

Step-by-step explanation:

We know that a general exponential function is like,y=a(b)^{x}

We can find the answer by hit and trial method by plugging the values of (x,y) coordinates.

Here we are going to solve this with the above general formula.

So as the points are (1,16) then for x=1,\ y=16

Can be arranged in terms of the general equation.

ab^1=16...equation(1) and ab^4=128...equation(2)

a\times b=16, then\ a=\frac{16}{a}

Plugging the values in equation 2.

We have

\frac{16}{b} b^4=128,16\times b^3=128,b=\sqrt[3]{\frac{128}{16}} =\sqrt[3]{8}=2

Plugging b=2 in equation 1.

We have a=\frac{16}{b} =\frac{16}{2} =8

Comparing with the general equation of exponential a=8 and b=2

So the function which depicts the above points =y=8(2)^x

From theoption we have B as the correct answer.

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(01.03. 106, 1.08 HC)
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Answer:

  A) see attached for a graph. Range: (-∞, 7]

  B) asymptotes: x = 1, y = -2, y = -1

  C) (x → -∞, y → -2), (x → ∞, y → -1)

Step-by-step explanation:

<h3>Part A</h3>

A graphing calculator is useful for graphing the function. We note that the part for x > 1 can be simplified:

  \dfrac{-x^2+x+2}{x^2-3x+2}=-\dfrac{(x-2)(x+1)}{(x-2)(x-1)}=-\dfrac{x+1}{x-1}\quad x\ne 2

This has a vertical asymptote at x=1, and a hole at x=2.

The function for x ≤ 1 is an ordinary exponential function, shifted left 1 unit and down 2 units. Its maximum value of 3^-2 = 7 is found at x=1.

The graph is attached.

The range of the function is (-∞, 7].

__

<h3>Part B</h3>

As we mentioned in Part A, there is a vertical asymptote at x = 1. This is where the denominator (x-1) is zero.

The exponential function has a horizontal asymptote of y = -2; the rational function has a horizontal asymptote of y = (-x/x) = -1. The horizontal asymptote of the exponential would ordinarily be y=0, but this function has been translated down 2 units.

__

<h3>Part C</h3>

The end behavior is defined by the horizontal asymptotes:

  for x → -∞, y → -2

  for x → ∞, y → -1

7 0
2 years ago
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