Answer:
Here is the complete question (attachment).
The function which represent the given points are 
Step-by-step explanation:
We know that a general exponential function is like,
We can find the answer by hit and trial method by plugging the values of
coordinates.
Here we are going to solve this with the above general formula.
So as the points are
then for 
Can be arranged in terms of the general equation.
...equation(1) and
...equation(2)

Plugging the values in equation 2.
We have
![\frac{16}{b} b^4=128,16\times b^3=128,b=\sqrt[3]{\frac{128}{16}} =\sqrt[3]{8}=2](https://tex.z-dn.net/?f=%5Cfrac%7B16%7D%7Bb%7D%20b%5E4%3D128%2C16%5Ctimes%20b%5E3%3D128%2Cb%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B128%7D%7B16%7D%7D%20%3D%5Csqrt%5B3%5D%7B8%7D%3D2)
Plugging
in equation 1.
We have 
Comparing with the general equation of exponential
and 
So the function which depicts the above points =
From theoption we have B as the correct answer.