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Shalnov [3]
4 years ago
7

Which exponential function goes through the points (1, 16) and (4, 128)?

Mathematics
1 answer:
djyliett [7]4 years ago
7 0

Answer:

Here is the complete question (attachment).

The function which represent the given points are f(x)=8(2)^{x}

Step-by-step explanation:

We know that a general exponential function is like,y=a(b)^{x}

We can find the answer by hit and trial method by plugging the values of (x,y) coordinates.

Here we are going to solve this with the above general formula.

So as the points are (1,16) then for x=1,\ y=16

Can be arranged in terms of the general equation.

ab^1=16...equation(1) and ab^4=128...equation(2)

a\times b=16, then\ a=\frac{16}{a}

Plugging the values in equation 2.

We have

\frac{16}{b} b^4=128,16\times b^3=128,b=\sqrt[3]{\frac{128}{16}} =\sqrt[3]{8}=2

Plugging b=2 in equation 1.

We have a=\frac{16}{b} =\frac{16}{2} =8

Comparing with the general equation of exponential a=8 and b=2

So the function which depicts the above points =y=8(2)^x

From theoption we have B as the correct answer.

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Answer:

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A true-false quiz with 10 questions was given to a statistics class. Following is the probability distribution for the score of
disa [49]

Answer:

E(X)=\sum_{i=1}^n X_i P(X_i)  

And if we use the values obtained we got:  

E(X)=5*0.05 +6*0.15 +7*0.33 +8*0.28+ 9*0.12 +10*0.07=7.48  

For this case this value means that the expected score is about 7.48

Step-by-step explanation:

For this case we assume the following probability distribution:

X         5       6         7       8        9        10

P(X)   0.05   0.15  0.33  0.28   0.12   0.07

First we need to find the expected value (first moment) and the second moment in order to find the variance and then the standard deviation.

In order to calculate the expected value we can use the following formula:  

E(X)=\sum_{i=1}^n X_i P(X_i)  

And if we use the values obtained we got:  

E(X)=5*0.05 +6*0.15 +7*0.33 +8*0.28+ 9*0.12 +10*0.07=7.48  

For this case this value means that the expected score is about 7.48

In order to find the standard deviation we need to find first the second moment, given by :  

E(X^2)=\sum_{i=1}^n X^2_i P(X_i)  

And using the formula we got:  

E(X^2)=(5^2 *0.05)+(6^2 *0.15)+(7^2 *0.33)+(8^2 *0.28)+ (9^2 *0.12 +(10^2 *0.07))=57.46  

Then we can find the variance with the following formula:  

Var(X)=E(X^2)-[E(X)]^2 =57.46-(7.48)^2 =1.5096  

And then the standard deviation would be given by:  

Sd(X)=\sqrt{Var(X)}=\sqrt{1.5096}=1.229  

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