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SVETLANKA909090 [29]
3 years ago
15

The number of perpendicular bisectors a segment can have is:

Mathematics
1 answer:
kirza4 [7]3 years ago
4 0

Answer:

0

Step-by-step explanation:

0co

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A horse farm is developing a new indoor arena in a rectangular buliding. They want the width of the building to be 3 wide feet a
erastovalidia [21]

Answer:

The area of the building in terms of y in its simplest form is 12(y + 2)

Step-by-step explanation:

Since the area of a rectangle is A = LW where L = length and W = width. From our question, the width of the rectangular building is 3 feet. So, W = 3 feet and its length is 4y + 8  feet. So, L = 4y + 8 feet.

So, the area of the building in terms of y is A = LW

= (4y + 8) × 3

Factorizing out 4 from the expression, we have

= 4(y + 2) × 3

= 12(y + 2)

So, the area of the building in terms of y in its simplest form is 12(y + 2)

8 0
3 years ago
Solve the system of equations using substitution
Andru [333]

Answer:

x = 136/11 , y = 68/11

Step-by-step explanation:

Solve the following system:

{6 x - y = 68

2 y = x

Hint: | Choose an equation and a variable to solve for.

In the second equation, look to solve for x:

{6 x - y = 68

2 y = x

Hint: | Reverse the equality in 2 y = x in order to isolate x to the left hand side.

2 y = x is equivalent to x = 2 y:

{6 x - y = 68

x = 2 y

Hint: | Perform a substitution.

Substitute x = 2 y into the first equation:

{11 y = 68

x = 2 y

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for y:

{11 y = 68

x = 2 y

Hint: | Solve for y.

Divide both sides by 11:

{y = 68/11

x = 2 y

Hint: | Perform a back substitution.

Substitute y = 68/11 into the second equation:

{y = 68/11

x = 136/11

Hint: | Sort results.

Collect results in alphabetical order:

Answer: {x = 136/11 , y = 68/11

7 0
3 years ago
PLSSS HELP ME!!!!! I WILL!!!! MARK!!!!!
Sunny_sXe [5.5K]

Answer:

23.1

Step-by-step explanation:

(4.2)(11)(0.5)

3 0
3 years ago
Can someone double check this please
Dmitry [639]

Answer: c. 29.65 + 0.90r ≤ 41

5 0
4 years ago
Assume the mean useful life of a particular light bulb is 2,000 hours and is normally distributed with a standard deviation of 3
Yuri [45]
The mean = 2,000
s = Sigma ( standard deviation ) = 300
M - 2 s = 2,000- 2 * 300 = 2,000 - 600 = 1,400
M + 2 s = 2,000 + 2 * 300 = 2,000 + 600 = 2,600
Answer.
Useful life of light bulbs within 2 standard deviations of the mean is:
A ) Between 1,400 and 2,600 hours
4 0
3 years ago
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