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Eduardwww [97]
3 years ago
15

6.

Mathematics
1 answer:
larisa86 [58]3 years ago
5 0

A. Every month Population will increase by a factor of 0.84%.

B.  Every 3 months Population will increase by a factor of 2.5%.

C. Increase in population in every 20 months is 10% + 6.72% = 16.72%.

<u>Step-by-step explanation:</u>

Here, we have  number of employees in a company has been growing exponentially by 10% each year. So , If we have population as x in year 2019 , an increase of 10% in population in 2020 as  x + \frac{x}{100}\times10 which is equivalent to \frac{11x}{10}.

<u>A.</u>

For each month: We have 12 months in a year and so, distributing 10% in 12 months would be like \frac{10}{12}  = 0.84 . ∴ Every month Population will increase by a factor of 0.84%.

<u>B.</u>

In every 3 months: We have , 12 months in a year , in order to check for every 3 months  \frac{12}{3} = 4 and Now, Population increase in every 3 months is \frac{10}{4}  = 2.5.  ∴ Every 3 months Population will increase by a factor of 2.5%.

<u>C.</u>

In every 20 months: We have , 12 months in a year in which increase in population is 10% . Left number of moths for which we have to calculate factor of increase in population is 20-12 = 8. For 1 month , there is 0.84% increase in population ∴ For 8 months , 8 × 0.84 = 6.72 %.

So , increase in population in every 20 months is 10% + 6.72% = 16.72%.

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That is not enough information.
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3 years ago
How do you construct a frequency distribution table using sturge’s approximation
artcher [175]

The steps to use to construct a frequency distribution table using sturge’s approximation is as below.

<h3>How to construct a frequency distribution table?</h3>

The steps to construct a frequency distribution table using Sturge's approximation are as follows;

Step 1: Find the range of the data: This is simply finding the difference between the largest and the smallest values.

Step 2; Take a decision on the approximate number of classes in which the given data are to be grouped. The formula for this is;

K = 1 + 3.322logN

where;

K= Number of classes

logN = Logarithm of the total number of observations.

Step 3; Determine the approximate class interval size: This is obtained by dividing the range of data by the number of classes and is denoted by h class interval size

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Step 5; Identify the remaining class boundaries: When you have gotten the lowest class boundary, then you can add the class interval size to the lower class boundary to get the upper class boundary.

Step 6; Distribute the data into respective classes:

Read more about  frequency distribution table at; brainly.com/question/27820465

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2 years ago
The speed(S) of a car varies partly directly as its mass(M) and partly directly as the quantity (Q) of fuel in it. When the spee
weeeeeb [17]

Answer:

S varies partly directly as M and Q.

S=C.

S=KMQ+C.

For the first one...

speed=80,m=220,Q=30.

80=K20×30+C.

80=600K+C......(I).equation one.

For the second one....

speed=60,m=300,Q=40.

60=K300×40+C.

60=12000K+C.....(ii). equation two.

Minus eqtn(I) from eqtn(ii).

80=600K+C.

- 60=12000K+C.

K=0.01754~0.018.

Substitute K=0.018 into eqtn(I).

80=600K+C

80=600×0.018+C.

80=10.8+C.

C=80-10.8=69.2.

The relation is S=0.018MQ+69.2

when speed is 100 and mass is 250 find the volume.

100=0.018×250×Q+69.2.

100=4.5Q+69.2.

4.5Q=100-69.2

4.5Q=30.8.

Q=30.8/4.5.

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6 0
3 years ago
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marshall27 [118]
Remark
Make up a proportion that relates the tree and its properties to the stick and its properties.

Givens
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Formula
s_h / s_s = x / t_s

Substitute and solve.
4/2 = x / 18  Cross multiply
4*18 = 2 * x
72 = 2x        Divide by 2
72/2 = x       
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The height of the tree is 36 feet.     
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slamgirl [31]

Answer:

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