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muminat
3 years ago
8

3.541 and 41 is repeated, what would it be as a simplified fraction?

Mathematics
1 answer:
qwelly [4]3 years ago
8 0

Answer: 3.5

Step-by-step explanation: Because the 4 and 1 aren’t big enough to change the 5 to go up the final answer would be 3.5 but if the 4 were to be a 5 or a number higher than the 5 would change to a 6.

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He counted 206 wheels and 170 pedals. How many bicycles and tricycles does he have.
noname [10]
Bicycle has 2 wheels and 2 pedals
 tricycle has 3 wheels and 2 pedals

EQ 1 : 2b + 2t = 170 pedals

 EQ 2: 2b +3t = 206 wheels

subtract  EQ 1 from EQ 2

2b +3t = 206 - 2b + 2t = 170 = t=36

 there were 36 tricycles

36 x 2 = 72 pedals

170 pedals - 72 = 98 pedals left
98/2 = 49 bicycles

36 Tricycles and 49 bicycles




8 0
3 years ago
You are asked to do a study of shelters for abused and battered women to determine the necessary capacity in your city to provid
ohaa [14]

Answer:

Using the normal probability distribution, with a capacity of 350, it is enough for all abused on 90.82% of nights.

274 shelters will be needed.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 250, \sigma = 75

If the city’s shelters have a capacity of 350, will that be enough places for abused women on 95% of all nights?

What is the percentile of 350?

This is the pvalue of Z when X = 350.

Z = \frac{X - \mu}{\sigma}

Z = \frac{250 - 150}{75}

Z = 1.33

Z = 1.33 has a pvalue of 0.9082.

Using the normal probability distribution, with a capacity of 350, it is enough for all abused on 90.82% of nights.

If not, what number of shelter openings will be needed?

The 95th percentile, which is X when Z = 1.645. So

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 150}{75}

X - 150 = 1.645*75

X = 274

274 shelters will be needed.

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