Let Fn be the number of ways of arranging such flagpole with the given conditions.
When arranging a flagpole of n feet high, consider the following cases
If the last flag used is a red flag, then the other flags are n-1 foot high, so they can be seen as arranged on a smaller flagpole of n-1 feet high, which can be done in Fn-1 ways.
Similarly, If the last flag used is a gold flag, then the other flags can be seen as arranged on a smaller flagpole of n-1 feet high. This can be done in Fn-1 ways.
If the last flag used is green, the other flags are n-2 feet high, so the flagpole can be arranged in Fn-2 ways.
Using the sum rule, we obtain that Fn = 2Fn-1 + Fn-2 for all n≥3. Listing all the combinations of flags, the initial conditions are F1 = 2 and F2 = 3.
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Answer:
he would have to buy 12 packs
Step-by-step explanation:
138/12=11.5
I am not sure but answer can be 1,5 or 96 and ir Can be wrong but ı am trying to help you
2 5/8 or 21/8. Use the Keep Change Flip method. Change the sign to multiplication and flip the second fraction.
Multiply the numerators and the denominators separatley.
This cannot be simplified further, but it can be converted to a mixed number (as opposed to an improper fraction).
Answer:
Lisa must get an 88.75 or higher to stay in between 80 and 90.
Step-by-step explanation: