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3 years ago

Sales Price 50 %What was the original price of a washing machine wholesale price is $285?

Mathematics

1 answer:

irakobra [83]3 years ago

4 0

Answer:

$570

Step-by-step explanation:

If 50% of the price is $285, all you have to do is mulipy 285 by 2. This would give you the answer of $570 as the orignal price of the washing machine.

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The roots of \[z^7 = -\frac{1}{\sqrt{2}} - \frac{i}{\sqrt{2}}\]are $\text{cis } \theta_1$, $\text{cis } \theta_2$, $\dots$, $\te

stepan [7]

Decoding the LaTeX that didn't render, we seek sum of the angles of the seventh roots of

$- \frac 1 {\sqrt 2} - \frac i {\sqrt{2}}$

That's on the unit circle, 45 degrees into the third quadrant, aka 225 degrees.

The seventh roots will all be separated by 360/7, around 51 degrees. The first seventh root has

$\theta_1 = 225^\circ / 7$

That's around 32 degrees.

The next angle is

$\theta_2 = \frac{1}{7}( 225^\circ + 360^\circ)$

The next one is

$\theta_3 = \frac{1}{7}( 225^\circ + 720^\circ)$

and in general

$\theta_n = \frac{1}{7}( 225^\circ + (n-1)360^\circ) = \frac 1 7(-135^\circ + 360^\circ n)$

$S = \displaystyle \sum_{n=1}^7 \theta_n = \frac{1}{7} \sum_{n=1}^7 -135^\circ + \frac{360}{7} \sum_{n=1}^7 n$

The first sum is just -135° since it's one seventh of the sum of seven -135s.

We have 1+2+3+4+5+6+7 = (1+7)+(2+6)+(3+5) + 4 = 28 so

$S = -135^\circ + 360^\circ (\frac{28} 7) = 4(360)-135 = 1305^\circ$

If I didn't screw it up, that means the answer is

Answer: 1305°

4 0

4 years ago

Combs and Stratton invested $140,000 and $360,000, respectively, in a partnership. They agreed to share net income in proportion

Phoenix [80]

Answer:

Comb's share will be = $12,180

Stratton's share will be = $31,320

Step-by-step explanation:

Given:

Comb's investment in the partnership = $140,000

Stratton's investment in the partnership = $360,000

The net income is shared in proportions of their investment.

Net income last year = $43,500

To find the share of each partner of the net income.

Solution:

Ratio of the investments of Comb to Stratton = $\frac{140,000}{360,000}$ $= \frac{14}{36}=\frac{7}{18}$ (Simplest ratio)

Thus, the investments must be shared in the ratio of 7 : 18

Let Comb's share in dollars be = $7x$

Then, Stratton's share in dollars = $18x$

Total net income can be given as = $7x+18x=25x$

Net income = $43,500

So, we have:

$25x=43,500$

Dividing both sides by 25.

$\frac{25x}{25}=\frac{43,500}{25}$

∴ $x=1740$

So, Comb's share will be = $7\times 1740 = \$12,180$

Stratton's share will be = $18\times 1740 = \$31,320$

7 0

3 years ago

Need help ASAP! Brainliest will be GRANTED to the right answer!

maksim [4K]

Length+height+width

5 0

3 years ago

Austin's truck has a mass of 2000 kg when traveling at 22.0 m/s, it brakes to a stop in 4.0 s. show that the magnitude of the br

olga2289 [7]

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3 years ago

Read 2 more answers

Julie and mark are selling wrapping paper for a school fundraiser. Julie sold 13 rolls of plain wrapping paper and 8 rolls of ho

patriot [66]

Answer:

Cost of one roll of plain wrapping paper is $12 and Cost of one roll of holiday paper is $17.

Step-by-step explanation:

Solution,

Let the cost of 1 plain wrapping paper be x.

And the cost of 1 holiday paper be y.

Julie sold 13 rolls of plain wrapping paper and 8 rolls of holiday paper and earns $292.

Total Money earned by Julie is equal to sum of number of wrapping paper multiplied with cost of wrapping paper and number of holiday paper multiplied with cost of holiday paper.

So we can frame it in equation form as;

$13x+8y=292\ \ \ \ \ equation\ 1$

Now, Mark sold 7 rolls of plain wrapping paper and 2 rolls of holiday paper and earns $118.

Total Money earned by Mark is equal to sum of number of wrapping paper multiplied with cost of wrapping paper and number of holiday paper multiplied with cost of holiday paper.

So we can frame it in equation form as;

$7x+2y=118\ \ \ \ \ equation\ 2$

Now Multiplying equation 2 by 4 we get;

$4(7x+2y)=118\times4\\\\4\times7x+4\times2y=118\times4\\\\28x+8y= 472 \ \ \ \ equation\ 3$

Now Subtracting equation 1 from equation 3.

$(28x+8y)-(13x+8y)= 472-292\\\\28x+8y-13x-8y= 180\\\\15x=180\\\\x=\frac{180}{2} = \$12$

Now substituting the value of x in equation 1 we get;

$13x+8y=292\\\\13\times12+8y=292\\\\156+8y=292\\\\8y=292-156\\\\8y=136\\\\y=\frac{136}{8}= \$17$

Hence Cost of one roll of plain wrapping paper is $12 and Cost of one roll of holiday paper is $17.

8 0

4 years ago