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3 years ago

Jhfxcvbjiuyfvbno Cccvhiihji nr

Mathematics

1 answer:

Rudiy273 years ago

7 0

Answer:

i agree

Step-by-step explanation:

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How many ways can you get to the end, only being able to go down or left, and having to avoid the green thing?

kirill [66]

I got 21, I give up.

6 0

2 years ago

You are driving 2760 miles across the country. During the first 3 days of your trip, you drive 1380 miles. If you continue to dr

prohojiy [21]

The entire trip will take 6 days.

(Encircle this answer, as said on the directions)

Step-by-step explanation:

We know that the first three days of the trip, we traveled 1380 miles.

Find the UNIT RATE of MILES PER day:

1380/3 = 460

Unit rate = 460 miles per day

If we were to drive at this (460 mi per day) rate EACH day and the whole journey takes 2760 miles across the country.

FInd the NUMBER of DAYS of the ENTIRE TRIP:

2760/460 = 6

It will take us 6 days to drive to the destination.

5 0

2 years ago

Please answer the question in the photo, thanks!

belka [17]

Answer:

$\therefore 2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}$

Step-by-step explanation:

The question relates to dividing a fraction by proper and another fraction

The given expression is presented as follows;

$2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right )$

We rearrange the fractions as improper fractions for easier division as follows;

$2\dfrac{1}{3} = \dfrac{7}{3}$

$-3\dfrac{2}{3} = -\dfrac{11}{3}$

Therefore, we have;

$2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = \dfrac{7}{3} \div \left (-\dfrac{11}{3} \right ) = \dfrac{7}{3} \times \left (\dfrac{1}{-\dfrac{11}{3} } \right ) = \dfrac{7}{3} \div \left (-\dfrac{3}{11} \right ) =-\dfrac{7}{11}$

$\therefore 2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}$

4 0

2 years ago

Express each quotient in the simplest form. 20xy^3/6z divided by 2xy/18z^5

Galina-37 [17]

$\dfrac{20xy^3}{6z}:\dfrac{2xy}{18z^5}=\dfrac{10xy^3}{3z}:\dfrac{xy}{9z^5}=\dfrac{10xy^3}{3z}\cdot\dfrac{9z^5}{xy}\\\\=\dfrac{10xy^3}{z}\cdot\dfrac{3z^5}{xy}=10y^2z^4\\\\\text{used:}\\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{a^n}{a^m}=a^{n-m}$

3 0

3 years ago

When you identify the author of a text, which of the following are you are specifically examining in the source?

ioda

I would say origin, but it's a hard choice.

3 0

3 years ago

Read 2 more answers