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3 years ago

Jhfxcvbjiuyfvbno Cccvhiihji nr

Mathematics

1 answer:

Rudiy273 years ago

7 0

Answer:

i agree

Step-by-step explanation:

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Brainliest answer!

pickupchik [31]

She added the check fee instead of subtracting it

8 0

3 years ago

The point P(7, −2) lies on the curve y = 2/(6 − x). (a) If Q is the point (x, 2/(6 − x)), use your calculator to find the slope

NARA [144]

Answer:

a) (i) $m = 2.22$ , (ii) $m = 2$ , (iii) $m = 2$ , (iv) $m = 2$ , (v) $m = 1.82$ , (vi) $m = 2$ , (vii) $m = 2$ , (viii) $m = 2$ ; b) $m \approx 2$ ; c) The equation of the tangent line to curve at P (7, -2) is $y = 2\cdot x + 12$ .

Step-by-step explanation:

a) The slope of the secant line PQ is represented by the following definition of slope:

$m = \frac{\Delta y}{\Delta x} = \frac{y_{Q}-y_{P}}{x_{Q}-x_{P}}$

(i) $x_{Q} = 6.9$ :

$y_{Q} =\frac{2}{6-6.9}$

$y_{Q} = -2.222$

$m = \frac{-2.222 + 2}{6.9-7}$

$m = 2.22$

(ii) $x_{Q} = 6.99$

$y_{Q} =\frac{2}{6-6.99}$

$y_{Q} = -2.020$

$m = \frac{-2.020 + 2}{6.99-7}$

$m = 2$

(iii) $x_{Q} = 6.999$

$y_{Q} =\frac{2}{6-6.999}$

$y_{Q} = -2.002$

$m = \frac{-2.002 + 2}{6.999-7}$

$m = 2$

(iv) $x_{Q} = 6.9999$

$y_{Q} =\frac{2}{6-6.9999}$

$y_{Q} = -2.0002$

$m = \frac{-2.0002 + 2}{6.9999-7}$

$m = 2$

(v) $x_{Q} = 7.1$

$y_{Q} =\frac{2}{6-7.1}$

$y_{Q} = -1.818$

$m = \frac{-1.818 + 2}{7.1-7}$

$m = 1.82$

(vi) $x_{Q} = 7.01$

$y_{Q} =\frac{2}{6-7.01}$

$y_{Q} = -1.980$

$m = \frac{-1.980 + 2}{7.01-7}$

$m = 2$

(vii) $x_{Q} = 7.001$

$y_{Q} =\frac{2}{6-7.001}$

$y_{Q} = -1.998$

$m = \frac{-1.998 + 2}{7.001-7}$

$m = 2$

(viii) $x_{Q} = 7.0001$

$y_{Q} =\frac{2}{6-7.0001}$

$y_{Q} = -1.9998$

$m = \frac{-1.9998 + 2}{7.0001-7}$

$m = 2$

b) The slope at P (7,-2) can be estimated by using the following average:

$m \approx \frac{f(6.9999)+f(7.0001)}{2}$

$m \approx \frac{2+2}{2}$

$m \approx 2$

The slope of the tangent line to the curve at P(7, -2) is 2.

c) The equation of the tangent line is a first-order polynomial with the following characteristics:

$y = m\cdot x + b$

Where:

$x$ - Independent variable.

$y$ - Depedent variable.

$m$ - Slope.

$b$ - x-Intercept.

The slope was found in point (b) (m = 2). Besides, the point of tangency (7,-2) is known and value of x-Intercept can be obtained after clearing the respective variable:

$-2 = 2 \cdot 7 + b$

$b = -2 + 14$

$b = 12$

The equation of the tangent line to curve at P (7, -2) is $y = 2\cdot x + 12$ .

7 0

3 years ago

The cost of 16 television sets is $640,160. What is the cost of 1 television set? (Round off the amount to the nearest thousand

Liono4ka [1.6K]

Answer:

$40000

Step-by-step explanation:

640160≈640000

640000/16=40000

5 0

3 years ago

Which function is odd? Check all that apply.

kvasek [131]

<em></em> $The\ function\ is\ odd\ if\ f(-x)=-f(x)\\\\We\ know:\\\sin x;\ \tan x\ and\ \cot x\ are\ odds.\\\cos x\ is\ even\ /\cos(-x)=\cos x/\\--------------------\\\\A.\ y=\sec x\\\\\sec(-x)=\dfrac{1}{\cos(-x)}=\dfrac{1}{\cos x}=\sec x-\fbox {NO}\\\\B.\ y=\sin x-\fbox{YES}\\\\C.\ y=\cot x\\\\\cot(-x)=\dfrac{\cos(-x)}{\sin(-x)}=\dfrac{\cos x}{-\sin x}=-\dfrac{\cos x}{\sin x}=-\cot x-\fbox{YES}\\\\D.\ y=\csc x\\\\\csc(-x)=\dfrac{1}{\sin(-x)}=\dfrac{1}{-\sin x}=-\dfrac{1}{\sin x}=-\csc x-\fbox{YES}$

6 0

3 years ago

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PLEASE HELP WILL GIVE BRAINLIEST TO CORRECT ANSWER

dem82 [27]

Ok so logically it would be the blue which is consistently low and unlike the others doesn't get any spikes of interst so BLUE.

8 0

3 years ago

Read 2 more answers