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mariarad [96]
3 years ago
14

Jhfxcvbjiuyfvbno Cccvhiihji nr

Mathematics
1 answer:
Rudiy273 years ago
7 0

Answer:

i agree

Step-by-step explanation:

jdkfhkjdf jajxjcj jdf o

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Please help me solve this question. Will make you the
zmey [24]

The relation you have shown is not a function.

In order to be a function, a relation's domain must be continuous in that no x-value is not repeated in any of the points. Since the first two points of the relation are (5,1) and (5,3), you can see that they have the same x-value, meaning that this is not a function.

One quick way you could test this is to quickly sketch a graph and use the vertical line test to see if the relation in question is a function. If it cross the vertical line once in all places, it is a function - if it crosses the vertical line more than once in any place, it is not a function.

6 0
3 years ago
How I can write 680,705 in expanded form
KatRina [158]
600,000+80,000+700+5
5 0
3 years ago
Read 2 more answers
1/8 into a decimal work
sergey [27]
Your answer is 0.125
4 0
3 years ago
Find the length of diagonal HJ. Round to the nearest hundredth.
Alisiya [41]

Answer:

The length of the diagonal HJ is 10.82 units

Step-by-step explanation:

* Lets revise the rule of the distance between two points

- d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}, where

 (x_{1},y_{1}) and (x_{2},y_{2}) are the two points

* Lets use this rule to find the length of the diagonal HJ

∵ The coordinates of point H are (-4 , 3)

∵ The coordinates of point J are (5 , -3)

∴ x_{1}=-4 and x_{2}=5

∴ y_{1}=3 and y_{2}=-3

- Lets find the length of the diagonal HJ by using the rule above

∴ HJ = \sqrt{(5-(-4))^{2}+(-3-3)^{2}}=\sqrt{(5+4)^{2}+(-6)^{2}}

∴ HJ = \sqrt{(9)^{2}+36}=\sqrt{81+36}=\sqrt{117}=10.81665

∴ HJ = 10.82

* The length of the diagonal HJ is 10.82 units

7 0
3 years ago
Which of the following number sentences is an example of the identity property of addition?
Paladinen [302]

Answer:

Option C is correct

8 + 0 = 8

Hope this helps!

:)

3 0
3 years ago
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