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Liula [17]
3 years ago
7

How to find a perimeter of a triangle

Mathematics
2 answers:
Illusion [34]3 years ago
6 0
The equation is P = a + b + c. Side plus base plus side
damaskus [11]3 years ago
5 0

Answer:

To find the perimeter of a triangle, add all the side lengths

Step-by-step explanation:

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HELP ME!!!
larisa [96]

Answer:

  -2, 8/3

Step-by-step explanation:

You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...

  A = (1/2)(f(a) +f(4))(4 -a)

  = (1/2)((3a -1) +(3·4 -1))(4 -a)

  = (1/2)(3a +10)(4 -a)

We want this area to be 12, so we can substitute that value for A and solve for "a".

  12 = (1/2)(3a +10)(4 -a)

 24 = (3a +10)(4 -a) = -3a² +2a +40

  3a² -2a -16 = 0 . . . . . . subtract the right side

  (3a -8)(a +2) = 0 . . . . . factor

Values of "a" that make these factors zero are ...

  a = 8/3, a = -2

The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.

_____

<em>Alternate solution</em>

The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.

5 0
3 years ago
What is the area of the trapezoid?<br> 68<br> 54<br> 76<br> 108
iren [92.7K]
108 is the answer for this question
6 0
2 years ago
Read 2 more answers
2r^2+3s^3-r^2+4t^2-r^2 if r=-2, s=-3, and t=5
dimulka [17.4K]
2(-2)^2+3(-3)^3-(-2)^2+4(5)^2-(-2)^2 = 19

19 is the answer.
3 0
3 years ago
The angle of the semicircle is:<br>a) 120<br>c) 180<br>b)60<br>d)90<br>​
AlexFokin [52]
Since there is no semicircle, the angle is 0.
8 0
3 years ago
Read 2 more answers
Can someone explain the answer to this and how to work it
9966 [12]
Your answer is 3/5, the picture below shows how sin cos tan work!

5 0
3 years ago
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