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spayn [35]
3 years ago
12

(3x+15) (6x+3) m<1 is

Mathematics
1 answer:
Allisa [31]3 years ago
8 0

Answer:

x = 4

Step-by-step explanation:

Simplifying

3x + 15 = 6x + 3

Reorder the terms:

15 + 3x = 6x + 3

Reorder the terms:

15 + 3x = 3 + 6x

Solving

15 + 3x = 3 + 6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x' to each side of the equation.

15 + 3x + -6x = 3 + 6x + -6x

Combine like terms: 3x + -6x = -3x

15 + -3x = 3 + 6x + -6x

Combine like terms: 6x + -6x = 0

15 + -3x = 3 + 0

15 + -3x = 3

Add '-15' to each side of the equation.

15 + -15 + -3x = 3 + -15

Combine like terms: 15 + -15 = 0

0 + -3x = 3 + -15

-3x = 3 + -15

Combine like terms: 3 + -15 = -12

-3x = -12

Divide each side by '-3'.

x = 4

Simplifying

x = 4

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Colin’s piano lesson is 45 minutes, or 3/4 of an hour, long. If he practices 6 different songs and spends an equal amount of tim
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Answer: \frac{1}{8} hour

Step-by-step explanation:

Given: The total time Collin spent on 6 songs =\frac{3}{4}\text{ hour}

Now, the fraction of an hour does he spend practicing each song is given by :-

\frac{\text{Total time taken}}{\text{Total songs}}=\frac{\frac{3}{4}}{6}=\frac{3}{4\times6}=\frac{1}{8}\text{hour}

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Can you help me with this word problem?​
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Answer:

The ratio of flour to sugar is 2:1

Step-by-step explanation:

Let f = weight of a bag of flour

Let s = weight of a bag of sugar

3f+2s = 32

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We have 2 equations and 2 unknowns, we can solve

4f=32

Divide by 4

4f/4 = 32/4

f = 8

Each bag of flour weights 8 pounds

Substitute this back into the first equation

3(8) +2s = 32

24+2s = 32

Subtract 24 from each side

24-24 +2s =32-24

2s = 8

Divide by 2

2s/2 = 8/2

s = 4 pounds

Flours weighs 8 pounds and sugar weights 4 pounds

We want the ratio of flour to sugar

Flour: sugar

8:4

We can divide each side by 4

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bogdanovich [222]

Answer:

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Step-by-step explanation:

.................

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KatRina [158]

1.

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Answer B)

2.

\frac{1}{3}\left(\frac{2}{15}x-\frac{2}{3}\right)>x+\frac{1}{5}\quad|\cdot3\\\\\\\frac{2}{15}x-\frac{2}{3}>3x+\frac{3}{5}\quad|\cdot15\\\\\\2x-\frac{30}{3}>45x+\frac{45}{5}\\\\2x-10>45x+9\\\\-10-9>45x-2x\\\\-19>43x\quad|:43\\\\\boxed{x

Answer B)

3.

\sqrt{14xy}\cdot\sqrt{12}\cdot\sqrt{30y}=\sqrt{14\cdot12\cdot30}\cdot\sqrt{xy^2}=\sqrt{2\cdot7\cdot3\cdot4\cdot2\cdot3\cdot5}\cdot\sqrt{xy^2}=\\\\=\sqrt{2^2\cdot3^2\cdot2^2\cdot5\cdot7}\cdot\sqrt{xy^2}=2\cdot3\cdot2\cdot\sqrt{35}\cdot y\cdot\sqrt{x}=\boxed{12y\sqrt{35x}}

3 0
4 years ago
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