Answer:
The first five belong in the left most group of 1/6 = 1/3÷2
The sixth (right) one belongs in the middle group of 1/9 = 1/3÷3
Step-by-step explanation:
Answer:
![\frac{x-8}{7}](https://tex.z-dn.net/?f=%5Cfrac%7Bx-8%7D%7B7%7D)
Step-by-step explanation:
A way to find the inverse function is to swap the x and y (f(x)) in the equation.
![y = 7x + 8\\x = 7y + 8\\x-8 = 7y\\y = \frac{x-8}{7}](https://tex.z-dn.net/?f=y%20%3D%207x%20%2B%208%5C%5Cx%20%3D%207y%20%2B%208%5C%5Cx-8%20%3D%207y%5C%5Cy%20%3D%20%5Cfrac%7Bx-8%7D%7B7%7D)
We can check that it is an inverse function by using a property of inverse functions:
![f(g(x)) = x](https://tex.z-dn.net/?f=f%28g%28x%29%29%20%3D%20x)
If we plug in the f(x) function into the variable x of the inverse function, we should end up with x
![y = \frac{(7x + 8) - 8}{7}\\y = \frac{7x}{7} \\y = x\\](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B%287x%20%2B%208%29%20-%208%7D%7B7%7D%5C%5Cy%20%3D%20%5Cfrac%7B7x%7D%7B7%7D%20%5C%5Cy%20%3D%20x%5C%5C)
It checks out!
Answer:
2nd graph (in the attached pics)
Step-by-step explanation:
Graphically, the <em>x-intercepts of the graph of a quadratic function are its zeroes. </em>
There can be
- no zeroes (where graph doesn't cut the x-axis at all),
- 1 zero (where graph touches the x-axis at one point only), and
- 2 zeros (where the graph cuts the x-axis at 2 points)
Looking at the figures, the 2nd graph has no real zeroes, <em>because the graph doesn't cut the x-axis at all!</em>
<em />
So, the answer is the second graph.
Answer:
<u> y = 19/36</u>
Step-by-step explanation:
Assuming that what you want is the value of y, you can pass all the right side stuff to the left, and the y to the right:
2/3 + 15/6 = 6y
Then you can sum the fractions on the left by using the same denominators:
4/6 + 15/6 = 6y ==> 19/6 = 6 * y
then you can pass the 6 that is multiplying on the right to the left - now dividing:
<u> y = 19/36</u>