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ella [17]
2 years ago
15

/2 }" alt="\frac{3/7}{7\sqrt{10}/2 }" align="absmiddle" class="latex-formula">How do I simplify this problem? I have radical in the denominator and a fraction in the numerator.
Mathematics
1 answer:
VashaNatasha [74]2 years ago
8 0

Multiply the numerator and denominator by 7×2 = 14 to eliminate the denominators of those fractions:

\dfrac{\dfrac37}{\dfrac{7\sqrt{10}}2}\times\dfrac{14}{14}=\dfrac{3\times2}{7\sqrt{10}\times7}=\dfrac6{49\sqrt{10}}

Rationalize the denominator by multiplying both numerator and denominator by √10:

\dfrac6{49\sqrt{10}}\times\dfrac{\sqrt{10}}{\sqrt{10}}=\dfrac{6\sqrt{10}}{49(\sqrt{10})^2}=\dfrac{6\sqrt{10}}{49\times10}=\dfrac{6\sqrt{10}}{490}

Lastly, cancel the common factor of 2 in both the numerator and denominator (which comes from 6 = 2×3 and 490 = 2×245):

\dfrac{6\sqrt{10}}{490}=\dfrac{3\sqrt{10}}{245}}

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Can someone help me with this?
creativ13 [48]

The missing values are 28° and 62°

<h3>What are perpendicular lines?</h3>

Perpendicular lines are said to be two lines that intersect or meet each other at right angles, that is 90 degrees.

From the information given, we have that;

Line AC ⊥ Line BE

Where:

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collect like terms

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Make 'x' the subject

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Thus, the missing values are 28° and 62°

Learn more about perpendicular lines here:

brainly.com/question/17683061

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