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3 years ago

How do you answer it and what's the answer

Mathematics

1 answer:

maksim [4K]3 years ago

4 0

These are vertical angles, meaning they’re congruent. Just set the two equal equations equal to each other and solve. 5x - 2 = 4x + 17

X = 19

5(19) - 2 = 4(19) + 17

95 - 2 = 76 + 17

93 = 93

Both angles are 93.

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Un bloc de la ville de New York a été représenté dans une grille. Chaque case contient un immeuble de

Andreas93 [3]

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2 years ago

Wrote and solve an equation to find the number.The difference of twice a number and 7 is 9

andrew11 [14]

n - 7 = 9

Step-by-step explanation:

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3 years ago

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krek1111 [17]

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3 years ago

Read 2 more answers

A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient

ankoles [38]

<u>Answer:</u>

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

<u>Solution:</u>

We need to show that the gradient of the curve at A is 1

Here given that ,

$y=(x-a) \sqrt{(x-b)}$ --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

$0=(b+1-a) \sqrt{(b+1-b)}$

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

$y^{\prime}=u^{\prime} y+y^{\prime} u$

so, we get

${u}^{\prime}=1$

$v^{\prime}=\frac{1}{2} \sqrt{(x-b)}$

$y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}$

By putting value of point A and putting value of eq 2 we get

$y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}$

$y^{\prime}=\frac{d y}{d x}=1$

Hence proved that the gradient of the curve at A is 1.

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2 years ago

What is the measure of each interior angle in a regular 24-gon?

kakasveta [241]

165 is what i got
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2 years ago