Question

Jerome, kevin and seth shared a submarine sandwhich. Jerome ate 1/2 of the sandwich , kevin ate 1/3 of the sandwich, and seth ate the rest. What is the ratio of jerome's share to kevin's share to kevin's share to seth's share?

Answer 1

Given:

Jerome ate 1/2 of the sandwich , Kevin ate 1/3 of the sandwich, and Seth ate the rest.

To find:

The ratio of jerome's share to kevin's share to seth's share.

Solution:

Jerome ate 1/2 of the sandwich. So,

Jerome's share = $\dfrac{1}{2}$

Kevin ate 1/3 of the sandwich. So,

Kevin's share = $\dfrac{1}{3}$

Seth ate the rest. So,

Seth's share = $1-\dfrac{1}{2}-\dfrac{1}{3}$

                     = $\dfrac{6-3-2}{6}$

                    = $\dfrac{1}{6}$

The ratio of jerome's share to kevin's share to seth's share is:

$\dfrac{1}{2}:\dfrac{1}{3}:\dfrac{1}{6}$

To simplify the ratio multiply the ratio by 6.

$\dfrac{1}{2}\times 6:\dfrac{1}{3}\times 6:\dfrac{1}{6}\times 6$

$3:2:1$

Therefore, the ratio of jerome's share to kevin's share to seth's share is 3:2:1.