Tenth blocks ones blocks
l l l l l l l o o
Answer:
Verified
Step-by-step explanation:
Let A matrix be in the form of
![\left[\begin{array}{cc}a&b\\c&d\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D)
Then det(A) = ad - bc
Matrix A transposed would be in the form of:
![\left[\begin{array}{cc}a&c\\b&d\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26c%5C%5Cb%26d%5Cend%7Barray%7D%5Cright%5D)
Where we can also calculate its determinant:
det(AT) = ad - bc = det(A)
So the determinant of the nxn matrix is the same as its transposed version for 2x2 matrices
<span>Krystal's rate = 1 floor in 16 min. = 1/16 floors per min.
Working together their rate = 1 floor in 5.76 min. = 1/5.76 floors per min.
We need to determine Perry's rate, so we need to equate their combined rate with the sum of the individual rates.
Let Perry's time = x
In equation form, we can write:
1/16 + 1/x = 1/5.76
Solve for x:
(x+16)/16x = 1/5.76 -> 5.76(x+16) = 16x -> 10.24x = 92.16 -> x = 9
So, Perry would take 9 mins. to do the floor alone.
I hope this helped!
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33 is the answer :) Please give me the brainliest answer, and a rate and thanks.
Ay^2+2ay-3a
a(y^2+2y-3)
a(y-1)(y+3)
