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Andreas93 [3]
3 years ago
6

Help pls!!

Mathematics
2 answers:
Elodia [21]3 years ago
6 0

Step-by-step explanation:

For this, we need to apply the Pythagoras theorem.

What this states?

It states that the sum of the squares of base and height of a right angle Triangle is equal to the square of hypotenuse of the triangle.

So, according to figure, a rectangle also has 90° angle.

65 being hypotenuse, 56 being base, we need height.

\rm{Height^2 = Hypotenuse^2 - Base^2}

\rm{Height^2 = (65)^2 - (56)^2}

\rm{Height = \sqrt{ 4225- 3136}}

\rm{Height = 33 \ metres}

And height is equal to x. So, 33 is the answer.

hodyreva [135]3 years ago
3 0

Answer:

C) 33 meters

Step-by-step explanation:

In this question, we need to find the value of the variable "x".

To do this, we must use the Pythagorean theorem: a² + b² = c²

Plug in your values and solve:

56² + b² = 65²

3,136 + b² = 65²

3,136 + b² = 4,225

Subtract 3,136 from both sides.

b² = 1,089

To cancel out the exponent, we would square root both sides.

√b² = √1,089

b = 33

This means that C) 33 meters will be your answer.

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Answer:

Partial Answer

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Step-by-step explanation:

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3 years ago
Write an<br> explicit formula for an, the nth term of the sequence 39, 43, 47, ....
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9514 1404 393

Answer:

  an = 39 +4(n -1)

Step-by-step explanation:

The formula for the general term of an arithmetic sequence is ...

  an = a1 +d(n -1)

Here, the sequence has first term a1 = 39 and common difference d = 43-39 = 4. So, the general term is ...

  an = 39 +4(n -1)

3 0
3 years ago
Solve the following quadratic equation for all values of x in simplest form.<br> 3(2 – 6)2 – 45 = 42
katovenus [111]

Answer:

u cant make it into simplest form

Step-by-step explanation:

the equation is false

7 0
3 years ago
X/x-2 + x-1/x+1= -1<br> Can someone walk me through the steps of this problem? Much appreciated. :)
stealth61 [152]

Answer:

x = 0 or x = 1

Step-by-step explanation:

Given equation:

\dfrac{x}{x-2}+\dfrac{x-1}{x+1}=-1

Multiply the two denominators to get the same denominator:

Multiply the numerator of the first fraction by the denominator of the second fraction to get the new numerator of the first fraction.

Multiply the numerator of the second fraction by the denominator of the first fraction to get the new numerator of the second fraction.

\implies \dfrac{x(x+1)}{(x-2)(x+1)}+\dfrac{(x-2)(x-1)}{(x-2)(x+1)}=-1

Add the numerators and keep the denominator so that there is now one fraction:

\implies \dfrac{x(x+1)+(x-2)(x-1)}{(x-2)(x+1)}=-1

Simplify the numerator by expanding the brackets:

\implies \dfrac{x^2+x+x^2-3x+2}{(x-2)(x+1)}=-1

\implies \dfrac{2x^2-2x+2}{(x-2)(x+1)}=-1

Simplify the denominator by expanding the brackets:

\implies \dfrac{2x^2-2x+2}{x^2-x-2}=-1

Multiply both sides by the denominator of the left side:

\implies 2x^2-2x+2=-1(x^2-x-2)

Simplify and move everything to the left side:

\implies 2x^2-2x+2=-x^2+x+2

\implies 3x^2-3x=0

Factor:

\implies 3x(x-1)=0

Therefore:

\implies 3x=0 \implies x=0

\implies x-1=0 \implies x=1

Therefore, x = 0 or x = 1

8 0
2 years ago
Read 2 more answers
Help me fast i need help a lot :3
Shtirlitz [24]

the third option

because 1/3 is not equal to three

where as if we replace the x with one in all the other we would find that the equation is correct.

8 0
3 years ago
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