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3 years ago

Tema: Máximo común divisor (MCD)

Mathematics

1 answer:

il63 [147K]3 years ago

4 0

Answer:

No hablo mucho español pero creo que estás buscando el mayor factor común? Seis se divide en 1, 2 y 4, pero no en 3. Si la pregunta está preguntando cuál no es divisible, entonces la respuesta es 3. Espero que ayude . . .

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Freddie is at chess practice waiting on his opponent's next move. He notices that the 4-inch-long minute hand is rotating around

aksik [14]

Part 1. Imagine a clock without the hour hand, When clock strikes 3:35, the minute hand is at 7. When it strikes 3:55, the minute hand is in 11. Each gap between two adjacent digits in the clock measures 30°. This is because a revolution divided by 12 is 360/12 = 30. Then, the angle between the minute hands in the picture is equal to 4(30°) = 120°. Know that π radians is equal to 180°. Converting 120° to radians,

120°(π radians/180°) = (2/3)π or 2.09 radians

Part 2. For this part, we determine the arc length intercepted by the angle 120° because this is the total distance travelled by the tip of the minute hand.

S = rθ, where θ is the angle in radians and r is the radius of the circle represented by the minute hand.
S = (4)(2.09)
S = 8.36 inches

Hence, the tip of the minute hand travelled a total distance of 8.36 inches.

4 0

3 years ago

Which is equivalent to 34?<br> O A) 3 X 4<br> O B) 4x3<br> O C) 4 X 4x4<br> O D) 3 x 3x3x3

Tpy6a [65]

The answer is d because all the other options are less than 34

8 0

4 years ago

Read 2 more answers

I. In a shipment of 300 connecting rods, the mean tensile strength is found to be 45 kpsi and has a standard deviation of 5 kpsi

CaHeK987 [17]

Answer:

a) Between 39 and 40 rods can be expected to have a strength less than 39.4 kpsi.

b) 260 rods are expected to have a strength between 39.4 and 60 kpsi

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 45, \sigma = 5$

(a) Assuming a normal distribution, how many rods can be expected to have a strength less than 39.4 kpsi?

The percentage of rods with a stength less than 39.4 is the pvalue of Z when X = 39.4. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{39.4 - 45}{5}$

$Z = -1.12$

$Z = -1.12$ has a pvalue of 0.1314

13.14% of rods have a strength less than 39.4 kpsi.

Out of 300

0.1314*300 = 39.42

Between 39 and 40 rods can be expected to have a strength less than 39.4 kpsi.

(b) How many are expected to have a strength between 39.4 and 60 kpsi?

The percentage of rods with a stength in this interval is the pvalue of Z when X = 60 subtracted by the pvalue of Z when X = 39.4. So

X = 60

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 45}{5}$

$Z = 3$

$Z = 3$ has a pvalue of 0.9987

X = 39.4

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{39.4 - 45}{5}$

$Z = -1.12$

$Z = -1.12$ has a pvalue of 0.1314

0.9987 - 0.1314 = 0.8673

86.73% of the rods are expected to have a strength between 39.4 and 60 kpsi

Out of 300

0.8673*300 = 260

260 rods are expected to have a strength between 39.4 and 60 kpsi

4 0

4 years ago

Round 5.458 to the nearest hundredth.

maxonik [38]

Answer:

Step-by-step explanation:

6 0

3 years ago

PLEASE FIND THE SURFACE AREA ASAP

Ilya [14]

Answer:

Ok ill help but please give me a lot of credit since i took the time to do it for you!

13 x 3 = 39, 39 x 2 = 78

9 x 3 = 27, 27 x 2 = 54

9 x 13 = 117, 117 x 2 = 234

234 + 78 + 54 = 366 mm

20 x 6 = 120, 120 x 2 = 240

4 x 20 = 80, 80 x 2 = 160

6 x 4 = 24, 24 x 2 = 48

240 + 160 + 48 = 448 cm

5 x 14 = 70, 70 x 2 = 140

5 x 16 = 80, 80 x 2 = 160

14 x 16 = 224 , 224 x 2 = 448

448 + 160 + 140 = 748 m

4 x 14 = 56, 56 x 2 = 112

17 x 4 = 68, 68 x 2 = 136

14 x 17 = 238, 238 x 2 = 476

476 + 112 + 136 = 724 ft

4 x 13 = 52, 52 x 2 = 104

13 x 19 = 247, 247 x 2 = 494

19 x 4 = 76, 76 x 2 = 152

104 + 494 + 152 = 750 in

14 x 9 = 126, 126 x 2 = 252

9 x 3 = 27, 27 x 2 = 54

3 x 14 = 42, 42 x 2 = 84

252 + 54 + 84 = 390 mm

7 x 12 = 84, 84 x 2 = 168

12 x 2 = 24, 24 x 2 = 48

2 x 7 = 14, 14 x 2 = 28

168 + 48 + 28 = 244 cm

6 x 4 = 24, 24 x 2 = 48

6 x 13 = 78, 78 x 2 = 156

4 x 13 = 52, 52 x 2 = 104

48 + 156 + 104 = 308 in

8 x 15 = 120, 120 x 2 = 240

4 x 15 = 60, 60 x 2 = 120

8 x 4 = 32, 32 x 2 = 64

240 + 120 + 64 = 424 ft

Please try to do 10 by yourself, thank you. Brainliest please.

6 0

3 years ago