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Tamiku [17]
3 years ago
12

Help me with this math function below!!

Mathematics
1 answer:
allsm [11]3 years ago
7 0
The answer is 6 . Why because 6 -12 =-6
The answer fir the second question mark is -22 . Why because -10-12 =-22
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Can someone please help me in this one??
Zarrin [17]
The correct answer is a. In the left-hand column, each number goes up by one. In the right hand column, each number goes up by 1120. Each number on the left can be multiplied by 1120 to get the number on the right.
7 0
3 years ago
Can someone please help me its urgent!!!!!!!!!!<br> 3x + 11 = 3x - 11
user100 [1]

Answer:

\Large\boxed{\mathsf{\Rightarrow NO\quad SOLUTIONS}}

Step-by-step explanation:

<h3><u>TO SOLVE:</u></h3>

Isolate by the x on one side of the equation.

<h3><u>SOLUTIONS:</u></h3>

First, subtract 3x from both sides.

\displaystyle \Rightarrow \mathsf{3x+11-3x=3x-11-3x}}

Solve.

\displaystyle \mathsf{11=-11}

Sides are NOT equal.

\Large\boxed{\mathsf{\Rightarrow THERE \quad ARE \quad NO \quad SOLUTIONS}}}

Therefore, there are no solutions.

6 0
3 years ago
I need some help with this calculus 1 question.
Cerrena [4.2K]

Answer:

(a) f'(1)=-4

(b) y+4x-4=0

Step-by-step explanation:

<u>Tangent Line of a Function</u>

Given f(x) a real differentiable function in x=a, the slope of the tangent line of the function in x=a is given by f'(x=a). Where f' is the first derivative of f.

We are given

y=x-x^5

The derivative is

y'=1-5x^4

(a) The slope of the tangent line at (1,0) is

f'(1)=1-5\cdot 1^4=-4

f'(1)=-4

(b) The equation of the tangent line can be found with the general formula of the line:

y-y_o=m(x-x_o)

Where m is the slope and the point (xo,yo) belongs to the line. We have m=-4, xo=1, yo=0, thus

y-0=-4(x-1)

Or, equivalently

y+4x-4=0

3 0
3 years ago
Whats <br> 3(x+4) In simplyed.
Setler [38]

Answer:

3x + 12

Step-by-step explanation:

Distribute the 3

5 0
4 years ago
Read 2 more answers
9j/5-6j simplify your answer. Type a interger or a fraction. Type your answer in the form a+bj
Serga [27]
Dividing by a complex number is a similar process to the above - we multiply top and bottom of the fraction by the conjugate of the bottom.
6 0
2 years ago
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