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ArbitrLikvidat [17]
3 years ago
7

\frac{3}{5} ) - 2" align="absmiddle" class="latex-formula">
simplify​
Mathematics
1 answer:
stealth61 [152]3 years ago
7 0
(3/5)-2= -7/5

-7/5= -1.4

Good luck !
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Mel and Nancy both worked hard over the summer. Together they earned a total of $525. Mel earned $75 more than Nancy.
Tomtit [17]

Answer:

M- 300

N- 225

Step-by-step explanation:

525 - 75 = 450

450/2= 225

225 + 75 = 300

7 0
3 years ago
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Using the given points, determine the slope. (8, 1) and (8, -4) slope = 0 slope = -5 slope is undefined
Sophie [7]
You find the slope by putting the points in the formula y2-y1/x2-x1

when you plug them in it should look like this

-4 -1/8-8
then you would add or subtract, when you do you would get

-5/0 
this can't be divide so the slope of this 2 points is undefined

Hope this helped
5 0
4 years ago
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What are the x intercepts is the function f(x)= x^2 + 3x-4
Paladinen [302]

Answer:

(1,0)(-4,0)

Step-by-step explanation:

4 0
3 years ago
What is the product of (-a+3)(a+4)
spin [16.1K]

Answer:

-a^2 -4a +3a +12

-a^2 -1a +12

Step-by-step explanation:

8 0
3 years ago
In analyzing hits by certain bombs in a​ war, an area was partitioned into 553 ​regions, each with an area of 0.95 km2. A total
Leto [7]

Answer:

Probability of having two hits in the same region = 0.178

mu: average number of hits per region

x: number of hits

e: mathematical constant approximately equal to 2.71828.

Step-by-step explanation:

We can describe the probability of k events with the Poisson distribution, expressed as:

P(x=k)=\frac{\mu^ke^{-\mu}}{k!}

Being μ the expected rate of events.

If 535 bombs hit 553 regions, the expected rate of bombs per region (the events for this question) is:

\mu=\frac{\#bombs}{\#regions} =\frac{535}{553}= 0.9674

For a region to being hit by two bombs, it has a probability of:

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4 0
3 years ago
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