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oksian1 [2.3K]
2 years ago
12

Mel and Nancy both worked hard over the summer. Together they earned a total of $525. Mel earned $75 more than Nancy.

Mathematics
2 answers:
Tomtit [17]2 years ago
7 0

Answer:

M- 300

N- 225

Step-by-step explanation:

525 - 75 = 450

450/2= 225

225 + 75 = 300

Rzqust [24]2 years ago
7 0
M-300

N-225. Hope it helps
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HELPPPPPPP on this question.! I need to pass.
timurjin [86]

9514 1404 393

Answer:

  12.25 (or -18.75)

Step-by-step explanation:

If you pay attention to the square of a binomial, ...

  (x -a)² = x² -2ax +a²

You see that the constant (a²) is the square of half the x-coefficient. That is, the x-coefficient is -2a, half that is -a, and the square of that is (-a)² = a².

In your equation, the x-coefficient is -7, half that is -3.5, and the square of that is 3.5² = 12.25.

So, you can think of this ambiguous question in a couple of ways.

<u>Concern is only with the x-terms</u>:

  x² -7x +31 = (x² -7x +12.25) +31 = 12.25 . . . . . . add 12.25 to both sides

  (x -3.5)² +31 = 12.25 . . . . write the x-terms as a square

<u>Concern with the equation overall</u>:

You want the end result to have the x-terms in the form of the square ...

  (x -3.5)² = x -7x +12.25

The left side of the equation can be put in that form by adding -18.75 to both sides;

  x² -7x +31 -18.75 = -18.75 . . . . . . add -18.75 to both sides

  x² -7x +12.25 = -18.75 . . . . . . . . . simplify

  (x -3.5)² = -18.75 . . . . . . write the left side as a square

__

The short of it is that we're not sure what the question is asking for exactly. The "help video" would probably clarify the intent. Most likely, you're concerned with adding the square of half the x-coefficient, 12.25.

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Let h be the function that assigns each student ID number to a grade level.
denis-greek [22]

Answer:

It is a function Jonny!

Step-by-step explanation:

Hello! I would say to Jonny:

Jonny! A function is a relation between two sets, in which every element of the first set (domain) is assigned only one element of the second set (codomain).

If you have serveral elements of the first set with the same corresponding element of the second set it is correct to call that relation a function.

However, if you have an element of the first set for which your relation can relate to more than one element of the second set, then Jonny, that is not a function.

In the present case, every student ID number can only be realted to a number of the set {9, 10, 11, 12}, a student cannot have more than one current grade level. Therefore, that relation is in fact a function

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