I'm working on the same thing right now and I'm using every resource in my hands right now to find a solution. I will edit this post when I have more. If you need any more help I have completed the previous activity and most of this one.
EDIT:
Ok so I checked with somebody who is pretty good with math and they said that 5x=5x would be right. Not too sure but that's what I'm putting.
I put EVERYTHING for this assignment in comments down below. Geez all of this for 5 freakin points.
-2(x+5) OR 2(-x-5) I hope that helps if not please let me know!
Answer:
(d) f(x) = -x²
Step-by-step explanation:
For the vertex of the quadratic function to be at the origin, both the x-term and the constant must be zero. That is, the function must be of the form ...
f(x) = a(x -h)² +k . . . . . . . . . . vertex form; vertex at (h, k)
f(x) = a(x -0)² +0 = ax² . . . . . vertex at the origin, (h, k) = (0, 0)
Of the offered answer choices, the only one with a vertex at the origin is ...
f(x) = -x² . . . . . a=-1
Answer:
a=6 or -6
Step-by-step explanation:
Solve the determinant to get a²-36=0
(a-6)(a+6)=0
a=6 or -6
