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AlexFokin [52]
3 years ago
6

Please can you explain how you got the answers! Thanks

Mathematics
2 answers:
CaHeK987 [17]3 years ago
7 0
KM - KL = LM
3x + 1.5 - (x + 0.5) = 3x - 2
3x + 1.5 - x - 0.5 = 3x - 2
2x + 1 = 3x - 2
1 + 2 = 3x - 2x
3 = x

so KM = 3(3) + 1.5 = 9 + 1.5 = 10.5
KL = x + 0.5 = 3 + 0.5 = 3.5
LM = 3x - 2 = 3(3) - 2 = 9 - 2 = 7 <===
Sedbober [7]3 years ago
4 0
First you have to find the measurement of the entire line,which will be equal x, than plug in in the equation between L and M 
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1. Find the cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of ₹ 3 per m
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1. Find the cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of ₹ 3 per m².

a = 51 m, b = 37 m, c = 20 m

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A=\sqrt{p(p-a)(p-b)(p-c)}\\\\A=\sqrt{54(54-51)(54-37)(54-20)}\\\\A=\sqrt{54\cdot3\cdot17\cdot34}\\\\A=\sqrt{9\cdot2\cdot3\cdot3\cdot17\cdot17\cdot2}\\\\A=3\cdot2\cdot3\cdot17\\\\A=306\,m^2

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2. Find the area of the isosceles triangle whose perimeter is 11 cm and the base is 5 cm.

a = 5 cm

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A=\sqrt{5.5(5.5-3)^2(5.5-5)}\\\\ A=\sqrt{5.5\cdot(2.5)^2\cdot0.5}\\\\ A=\sqrt{11\cdot0.5\cdot(2.5)^2\cdot0.5}\\\\A=0.5\cdot2.5\cdot\sqrt{11}\\\\A=1.25\sqrt{11}\,cm^2\approx4.146\,cm^2

3. Find the area of the equilateral triangle whose each side is 8 cm.

a = b = c = 8 cm

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A=\sqrt{12(12-8)^3}\\\\ A=\sqrt{12\cdot4^3}\\\\ A=\sqrt{3\cdot4\cdot4\cdot4^2}\\\\A=4\cdot4\cdot\sqrt{3}\\\\A=16\sqrt3\ cm^2\approx27.713\ cm^2

4. The perimeter of an isosceles triangle is 32 cm. The ratio of the equal side to its base is 3 : 2. Find the area of the triangle.

a = 2x

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8 0
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