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3 years ago

THIS IS MY LAST QUESTION AND ITS DUE RIGHT NOW

Mathematics

2 answers:

ivanzaharov [21]3 years ago

7 0

Answer:

Step-by-step explanation:

Mariulka [41]3 years ago

5 0

Answer:

IT would b B

Step-by-step explanation:

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At the market, 777 apples cost \$4.55$4.55dollar sign, 4, point, 55. how much do 999 apples cost? \$

vredina [299]

I divided $.55 by 777 and got 0.00585 cents per apple. Then I mulitplied 0.00585 by 999 and got $5.85.

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3 years ago

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astraxan [27]

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3 years ago

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3x-5y+6 how many terms are in this expression

djyliett [7]

3 terms are in the expression

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3 years ago

Simplify (4x+2)3 please for my

Mademuasel [1]

Answer:

(4x + 2) x 3

4x + 2 x 3

4x + 6

4x/4 = X + 6/4 = 1.5

X = 1.5 I think

P.S. hope this helped if it is correct may I get Brainliest

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3 years ago

Suppose that water is pouring into a swimming pool in the shape of a right circular cylinder at a constant rate of 3 cubic feet

gtnhenbr [62]

Answer:

Therefore the height of the water in the pool changes at the rate of $\frac{1}{3\pi}$ feet per minute.

Step-by-step explanation:

Given that the shape of swimming pool is right circular cylinder.

The rate of water pouring in the pool = 3 cubic feet per minute.

It means the rate of change of volume is 3 cubic feet per minute.

$\frac{dv}{dt}=3$ cubic feet per minute.

When the volume of the swimming pool changed it means the height of the water level of the pool change and the radius of the swimming pool remains constant.

Let the height of the pool be h.

The volume of the pool is = $\pi 3^2 h$ cubic feet

$=9\pi h$ cubic feet

Therefore,

v $=9\pi h$

Differentiating with respect to t

$\frac{dv}{dt}= 9\pi \frac{dh}{dt}$

Putting $\frac{dv}{dt}=3$

$3=9\pi \frac{dh}{dt}$

$\Rightarrow \frac{dh}{dt} =\frac{3}{9\pi}$

$\Rightarrow \frac{dh}{dt} =\frac{1}{3\pi}$

The change of height of the pool does not depend on the depth of the pool.

Therefore the rate of change of height of the water in the pool is $\frac{1}{3\pi}$ feet per minute.

6 0

3 years ago