Answer: 12
Step-by-step explanation:
Given the question :
Given the four digits 2, 4, 6, and 7, how many different positive two-digit integers can be formed using these digits if a digit may not be repeated in an integer?
The number of different positive two integer number can be obtained by:
P(4, 2) = 4P2
Recall:
nPr = n! / (n - r)!
4P2 = 4! / (4 - 2)!
4P2 = 4! / 2!
4P2 = (4 * 3 * 2 * 1) / ( 2 * 1)
4P2 = 24 / 2
4P2 = 12
Hence, 12 different positive two-digit integers can be formed using these digits if a digit may not be repeated in an integer
Answer:
3 of them should have sprinkles.
Step-by-step explanation:
Answer:
(2x-1)(x+3)
Step-by-step explanation:
2x(x+3)-1(x+3)
(2x-1)(x+3)
Answer:
34
Step-by-step explanation:
Straight lines are 180 degrees, so the angle inside of the triangle next to the 127, is 53 degrees. (180-127= 53)
So to find "x", we need to figure out what the full number is.
59+53 = 112.
180-112= 68.
Now that we have the degree of the full angle, we can make an equation to find x.
x*2 = 68
(Divide 2 from both sides to isolate the variable)
x = 34
I hope this helped!
((There has been a malfunction or this users account may have been deleted))).....))
