The coefficients in the balanced reaction
<u>4</u> Fe + <u>3</u> O₂ → <u>2</u> Fe₂O₃
represent the ratio of moles of each reactant to each product. That is, for every 4 moles of Fe and 3 moles of O₂, 2 moles of Fe₂O₃ are produced.
First convert the given amount of Fe into moles. Fe has a molar mass of 55.845 g/mol, so you have
42.7 g × (1/55.845 mol/g) = 0.765 mol
of Fe.
Find how many moles of Fe₂O₃ are produced given this much Fe and an abundant supply of O₂. Multiply the coefficients of the balanced reaction by 0.765/4 :
<u>0.765</u> Fe + <u>0.573</u> O₂ → <u>0.382</u> Fe₂O₃
Now convert the amount of Fe₂O₃ to grams. O has a molar mass of 15.999 g/mol, so Fe₂O₃ has a total molar mass of about
2 (55.845 g/mol) + 3 (15.999 g/mol) = 159.687 g/mol
Then the reaction would produce about
0.382 mol × (158.687 g/mol) ≈ 61.0 g
of Fe₂O₃.
Answer:
the answer is d
Step-by-step explanation:
Answer:
the answer is 10
Step-by-step explanation:
sorry it took so long i had to do something
Okay so, I am assuming the model is smaller so it would be 0.34m long.
The model has to be 200 times smaller than the actual plane
Divide 68/200 and you get 0.34
Then to check your answer, multiply 0.34 by 200 which is 68 meaning
0.34:68 is equal to 1:200
Assuming the model is bigger (just in case) it would be 13,600m long.
The in this scenario, the model has to be 200 times bigger so it would be 68(200) which is 13,600
Hope this helps
500 cubic feet of 1/2-inch thick stainless steel plates will weigh the same no matter what dimensions are use for area and height of tank.
A 5 foot by 5 foot area 20 feet high (500 cubic feet) will weigh just as much as a 10 foot by 10 foot area 5 feet high (also 500 cubic feet) since you are using the same amount of material for the whole tank. Only possible change in weight of tank is the use of welding material and how evenly and good the welder is at welding stainless steel.
