All categories

3 years ago

A 8-kg load stretches an elastic belt 0.02 m. How much will a 12-kg load stretch the belt?

Mathematics

1 answer:

vazorg [7]3 years ago

8 0

Answer:

A 12-kg load stretches an elastic the belt 0.03m

Step-by-step explanation:

we know A 8-kg load stretches an elastic belt 0.02 m.

=> 0.02 / 8 = 0.0025

so A 1-kg load can stretch an elastic belt 0.02 m.

=> 12 * 0.0025 = 0.03 m

A 12-kg load stretches an elastic the belt 0.03m

You might be interested in

I need help to figure this out.

Sloan [31]

Answer:

$\frac{1}{4} = \frac{5}{20}$

$\frac{2}{5} = \frac{8}{20}$

$\frac{1}{4} < \frac{2}{5}$

7 0

2 years ago

Read 2 more answers

Caculate the sale price to two decimal places of an item which is sold at a discount of $95.64 to its regular price of $546.59.

sattari [20]

Answer: 450.95

Step-by-step explanation:

3 0

3 years ago

Hello , how to do 6(iii)?

Doss [256]

Answer:

$\displaystyle \frac{dS}{dt}=\frac{3}{50r}$

Step-by-step explanation:

Water is being pumped into an inflated rubber sphere at a constant rate of 0.03 cubic meters per second.

So, dV/dt = 0.03.

We want to show that dS/dt is directly proportional to 1/r.

In other words, we want to establish the relationship that dS/dt = k(1/r), where k is some constant.

First, the volume of a sphere V is given by:

$\displaystyle V=\frac{4}{3}\pi r^3$

Therefore:

$\displaystyle \frac{dV}{dt}=4\pi r^2\frac{dr}{dt}$

Next, the surface area of a sphere S is given by:

$\displaystyle S=4\pi r^2$

Therefore:

$\displaystyle \frac{dS}{dt}=8\pi r\frac{dr}{dt}$

We can divide both sides by 2:

$\displaystyle \frac{1}{2}\frac{dS}{dt}=4\pi r\frac{dr}{dt}$

We can substitute this into dV/dt. Rewriting:

$\displaystyle \frac{dV}{dt}=r\Big(4\pi r\frac{dr}{dt}\Big)$

So:

$\displaystyle \frac{dV}{dt}=\frac{1}{2}r\frac{dS}{dt}$

Since dV/dt = 0.03 or 3/100:

$\displaystyle \frac{3}{100}=\frac{1}{2}r\frac{dS}{dt}$

Therefore:

$\displaystyle \frac{dS}{dt}=\frac{3}{50r}=\frac{3}{50}\Big(\frac{1}{r}\Big)$

Where k = 3/50.

And we have shown that dS/dt is directly proportional to 1/r.

4 0

3 years ago

9 Find mZWVT T 35x-2 U 93 ° W V 7x + 5 mZWVT =

nikitadnepr [17]

Answer:

Step-by-step explanation:

$\frac{35x - 2 - 93}{2} = 7x + 5$

$\frac{35x - 95}{2 } = 7x + 5$

$17.5x - 47.5 = 7x + 5$

$17.5x = 7x + 52.5$

$10.5x = 52.5$

$x = 5$

Plug 5 in for 7x+5.

$7(5) + 5 = 40$

3 0

2 years ago

I need help with answering this equation

Sloan [31]

Answer:

in this case it is just multiplying the two items together

the THIRD CHOICE...

3x(x^2-5x-9)

3x^3 -15x^2 -27x

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers