A 8-kg load stretches an elastic belt 0.02 m. How much will a 12-kg load stretch the belt?

Mathematics

1 answer:

vazorg [7]3 years ago

8 0

Answer:

A 12-kg load stretches an elastic the belt 0.03m

Step-by-step explanation:

we know A 8-kg load stretches an elastic belt 0.02 m.

=> 0.02 / 8 = 0.0025

so A 1-kg load can stretch an elastic belt 0.02 m.

=> 12 * 0.0025 = 0.03 m

A 12-kg load stretches an elastic the belt 0.03m

You might be interested in

A farm equipment company kept a record of the number of tractors made each month. What is the mean of the numbers? ANSWERS

Marat540 [252]

The answer I got is 8

7 0

3 years ago

Help me out please.i will give brainly

tankabanditka [31]

Answer:

Hello! answer: 17

Step-by-step explanation:

Assuming this is the Pythagorean theorem our formula would be

a^2 + b^2 = c^2

meaning both of those sides multiplied by themselves added together will equal a number which is the result of c multiplied byitself sorry it sounds confused but...

15 × 15 = 225 8 × 8 = 64 225 + 64 = 289

the square root or the (number multiplied byitself that equals 289) is 17 because

17 × 17 = 289 so × = 17 I hope that helps!

7 0

3 years ago

Read 2 more answers

Leah is writing an equivalent equation which solves for y. What should be her next step? 3x+4y=8 Add 4y to both sides of the equ

ratelena [41]

The given equation is

$3x+4y=8$

And we have to solve for y.

Solving for y, means isolating y . And to isolate y, we need to get rid of 4 that is with y .

It means we have to separate 4 from y, and for separation , we have to perform division. That is, we have to divide both sides by 4, and that will be the next step .

So out of the four options, correct option is the last option .

4 0

3 years ago

Read 2 more answers

Krishaun has $5, $10, and $20 coins worth a total of $560. She has the same number of $5 coins as $10 coins, and the same number

valkas [14]

f = t = n five ten and twenty

5n + 10n + 20n = 560

35n = 560

n = twenty dollar coins = 16

4 0

3 years ago