Keisha and David each found the same value for cosine theta, as shown below, given Sine theta = Negative StartFraction 8 Over 17
EndFraction. Keisha’s Solution David’s Solution Tangent squared theta + 1 = secant squared theta. StartFraction sine squared theta Over cosine squared theta EndFraction + 1 = StartFraction 1 Over cosine squared theta EndFraction. StartFraction (eight-seventeenths) squared Over cosine squared theta EndFraction + 1 = StartFraction 1 Over cosine squared theta EndFraction. (eight-seventeenths) squared + cosine squared theta = 1. cosine theta = plus-or-minus StartRoot 1 minus StartFraction 64 Over 289 EndFraction EndRoot. cosine theta = plus-or-minus Fifteen-seventeenths sine squared theta + cosine squared theta = 1. cosine squared theta = 1 minus (negative eight-seventeenths) squared. cosine theta = plus-or-minus StartRoot StartFraction 225 Over 289 EndFraction EndRoot. Cosine theta = plus-or-minus fifteen-seventeenths Whose procedure is correct? Keisha’s procedure is correct. David’s procedure is correct. Both procedures are correct. Neither procedure is correct.
2 answers:
Answer:
C) Both procedures are correct
Step-by-step explanation:
1 + tan²(theta) = sec²(theta)
And
cos²(theta) = 1 - sin²(theta)
Are both valid identities
Answer:
c) both are correct
Step-by-step explanation:
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<h3>x = -3 , x = 3</h3>
Step-by-step explanation:
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