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Charra [1.4K]
3 years ago
7

Keisha and David each found the same value for cosine theta, as shown below, given Sine theta = Negative StartFraction 8 Over 17

EndFraction. Keisha’s Solution David’s Solution Tangent squared theta + 1 = secant squared theta. StartFraction sine squared theta Over cosine squared theta EndFraction + 1 = StartFraction 1 Over cosine squared theta EndFraction. StartFraction (eight-seventeenths) squared Over cosine squared theta EndFraction + 1 = StartFraction 1 Over cosine squared theta EndFraction. (eight-seventeenths) squared + cosine squared theta = 1. cosine theta = plus-or-minus StartRoot 1 minus StartFraction 64 Over 289 EndFraction EndRoot. cosine theta = plus-or-minus Fifteen-seventeenths sine squared theta + cosine squared theta = 1. cosine squared theta = 1 minus (negative eight-seventeenths) squared. cosine theta = plus-or-minus StartRoot StartFraction 225 Over 289 EndFraction EndRoot. Cosine theta = plus-or-minus fifteen-seventeenths Whose procedure is correct? Keisha’s procedure is correct. David’s procedure is correct. Both procedures are correct. Neither procedure is correct.
Mathematics
2 answers:
AURORKA [14]3 years ago
8 0

Answer:

C) Both procedures are correct

Step-by-step explanation:

1 + tan²(theta) = sec²(theta)

And

cos²(theta) = 1 - sin²(theta)

Are both valid identities

monitta3 years ago
8 0

Answer:

c) both are correct

Step-by-step explanation:

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Given the equation 4x2 − 8x + 20 = 0, what are the values of h and k when the equation is written in vertex form a(x − h)2 + k =
GenaCL600 [577]

Answer:

The correct option is:

h = 1, k = 16

Step-by-step explanation:

y=4x^2-8x+20 =0

It is a quadratic formula in standard form:

ax^2+bx+c

where a = 4 , b = -8 and c=20

The vertex form is:

a(x − h)2 + k = 0

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Calculate h according to the following formula:

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h = 8/8

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k = 4-8+20

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Thus the correct option is h=1, k=16....

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lisov135 [29]

Answer:

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<em><u>explanation in the pic above</u></em>

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