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Charra [1.4K]
3 years ago
7

Keisha and David each found the same value for cosine theta, as shown below, given Sine theta = Negative StartFraction 8 Over 17

EndFraction. Keisha’s Solution David’s Solution Tangent squared theta + 1 = secant squared theta. StartFraction sine squared theta Over cosine squared theta EndFraction + 1 = StartFraction 1 Over cosine squared theta EndFraction. StartFraction (eight-seventeenths) squared Over cosine squared theta EndFraction + 1 = StartFraction 1 Over cosine squared theta EndFraction. (eight-seventeenths) squared + cosine squared theta = 1. cosine theta = plus-or-minus StartRoot 1 minus StartFraction 64 Over 289 EndFraction EndRoot. cosine theta = plus-or-minus Fifteen-seventeenths sine squared theta + cosine squared theta = 1. cosine squared theta = 1 minus (negative eight-seventeenths) squared. cosine theta = plus-or-minus StartRoot StartFraction 225 Over 289 EndFraction EndRoot. Cosine theta = plus-or-minus fifteen-seventeenths Whose procedure is correct? Keisha’s procedure is correct. David’s procedure is correct. Both procedures are correct. Neither procedure is correct.
Mathematics
2 answers:
AURORKA [14]3 years ago
8 0

Answer:

C) Both procedures are correct

Step-by-step explanation:

1 + tan²(theta) = sec²(theta)

And

cos²(theta) = 1 - sin²(theta)

Are both valid identities

monitta3 years ago
8 0

Answer:

c) both are correct

Step-by-step explanation:

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Please help! Thank you!
KIM [24]
The correct answer is:  [B]:  " (2, 5) ".
__________________________________________
Given:
__________________________________________
  -5x + y = -5 ;
  -4x + 2y = 2 .
___________________________________________
  Consider the first equation:
___________________________
-5x + y = -5 ;  ↔ y + (-5x) = -5 ;

↔ y - 5x = -5 ;  Add "5x" to each side of the equation; to isolate "y" on one side of the equation; and to solve in terms of "y".
_____________________________________________
   y - 5x + 5x = -5 + 5x  

   y = -5 + 5x ;  ↔ y = 5x - 5 ;
____________________________________________
 Now, take our second equation:
______________________________
     -4x + 2y = 2 ; and plug in "(5x - 5)" for "y" ;  and solve for "x" :
_____________________________________________________
         -4x + 2(5x - 5) = 2 ; 
______________________________________________________
Note, 2(5x - 5) = 2(5x) - 2(5)  = 10x - 10 ;
__________________________________________
So:   -4x + 10x - 10 = 2 ;

On the left-hand side of the equation, combine the "like terms" ;

-4x +10x = 6x ;  and rewrite:

6x - 10 = 2  ;

Now, add "10" to each side of the equation:

6x - 10 + 10 = 2 + 10 ;

to get:

           6x = 12 ;  Now, divide EACH side of the equation by "6" ; to isolate "x" on one side of the equation; and to solve for "x" ; 

           6x/6 = 12 / 6 ;
 
                 x = 2 ;
_________________________________
Now, take our first given equation; and plug our solved value for "x" ; which is "2" ; and solve for "y" ;
_____________________________________
-5x + y = -5  ;

-5(2) + y = -5 ;

-10 + y = -5 ;  ↔
                              y - 10 = -5  ;

Add "10" to each side of the equation; to isolate "y" on one side of the equation; and to solve for "y" ;
     
         y - 10 + 10 = -5 + 10 ;

                   y = 5 .
_____________________________
So, we have, x = 2 ; and y = 5 .
____________________________
Now, let us check our work by plugging in "2" for "x" and "5" for "y" in BOTH the original first and second equations:
______________________________
first equation: 

-5x + y = -5 ;

-5(2) + 5 =? -5?

-10 + 5 =? -5 ? YES!
______________________
second equation:

-4x + 2y = 2 ;

-4(2) + 2(5) =? 2 ?

-8 + 10 =? 2 ?  Yes!
_______________________________________________________
So, the answer is: 
___________________________________________________________
          x = 2 , y = 5 ; or, "(2, 5)" ;  which is: "Answer choice: [B] " .
___________________________________________________________



3 0
3 years ago
Now see if you can solve these word problems about time and distance.
ladessa [460]

Answer:

3.5 hours

Step-by-step explanation:

Ediburgh -------------------------------350 miles-------------------------London

Let the distance traveled by train from Edin to London be "x"

hence the distance traveled by train from London to Edin would be "350-x"

  • The rate of Edin to London train is 60
  • The rate of London to Edin train is 40

Let the time they meet be"t"

Now, we know distance formula to be D = RT

Where

D is distance

R is rate

and

T is time

<u>Train from Edin to London:</u>

x = 60t

<u>Train from London to Edin:</u>

350-x = 40t

Solving for x:

350 - 40t = x

We put this into first equation:

x = 60t

350 - 40t = 60t

350 = 100t

t = 350/100

t = 3.5

They meet after 3.5 hours

4 0
3 years ago
Consider the expression √(√625).
const2013 [10]

Answer:

5

Step-by-step explanation:

Square Root - Finding a number that multiplies itself twice into the number within the square root

With this meaning, we need to find a number that multiplies itself into 625.

Finding calculations using exponents will help,

25^2 is equal to 625. Therefore \sqrt{25}

We are not finished, as there is another square root right after, empowering the parenthesis, so what number multiplies itself equals 25?

This would be 5, therefore \sqrt{(\sqrt{625}) } is equal to 5.

6 0
3 years ago
Complete the statement<br> 134.7 g= blank mg
pishuonlain [190]

i also need help on this question i have a big test tommorow this will really help me

4 0
3 years ago
Triangle FGH has the following side lengths: FG = 5 ft, GH = 10 ft, HF = 12 ft Triangle PQR is similar to triangle FGH. The long
7nadin3 [17]
The first thing we must do for this case is find the scale factor.
 We have then that for the larger side of both triangle, the scale factor is:
 k =  \frac{RP}{HF}
 k = \frac{7.2}{12}
 k = 0.6
 To find the other two sides, we must apply the scale factor on each side of the triangle FGH.
 We have then:

 For PQ
 
PQ = k * FG&#10;&#10;PQ = 0.6 * 5&#10;&#10;PQ = 3

 For QR
 
QR = k * GH&#10;&#10;QR = 0.6 * 10&#10;&#10;QR = 6

 Answer:
 
You have that the lengths for the other two sides of triangle PQR are:
 
PQ = 3&#10;&#10;QR = 6
3 0
3 years ago
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