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Nat2105 [25]
3 years ago
8

What is -5x-5(8x)=0 solve for x

Mathematics
2 answers:
gavmur [86]3 years ago
7 0
Multiply -5 and 8x to get -40x
then subtract 40x from -5x to get -45x
lastly divide 0 by -45 to get 0
x=0
hope this helps :)
kolbaska11 [484]3 years ago
4 0
-45(x) = 0 {Solve this}
  Now, lets multiply (×) by both sides of the problem 
   45{x} = 0 
Divide each of the sides of the problems by the number 45 
So, this means that the value of x is probably going to be 0 ; x = 0 
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Plz help <br> decrease 420 by 7%
UNO [17]
So you would work out
5%= 21
and then you would need to work out 2%
1%=4.2
2%=8.4
21+8.4
=29.4
420-29.4
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7 0
2 years ago
PLEASE HELP!!
omeli [17]

Answer:

34

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the length of TH, when T (10,7), and H (-4,3)?
drek231 [11]

Answer:

TH=14.56

Step-by-step explanation:

Given: T(10,7) and H(-4,3)

Distance formula: d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

\text{Length of TH }=\sqrt{(-4-10)^2+(3-7)^2}

                           =\sqrt{14^2+4^2}

                           =\sqrt{196+16}

                           =\sqrt{212}

                           \approx 14.56

Hence, The length of TH \sqrt{212}\approx 14.56

5 0
3 years ago
What is the value of the expression -3x²y + 4x
pogonyaev
The answer of this question is A. -112
5 0
2 years ago
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On a very hot summer day, 5% of the production employees at Midland States Steel are absent from work. The production employees
Ann [662]

Answer:

59.87% probability of randomly selecting 10 production employees on a hot summer day and finding that none of them are absent

Step-by-step explanation:

For each employee, there are only two possible outcomes. Either they are absent, or they are not. The probability of an employee being absent is independent from other employees. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5% of the production employees at Midland States Steel are absent from work.

This means that p = 0.05

What is the probability of randomly selecting 10 production employees on a hot summer day and finding that none of them are absent

This is P(X = 0) when n = 10. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.05)^{0}.(0.95)^{10} = 0.5987

59.87% probability of randomly selecting 10 production employees on a hot summer day and finding that none of them are absent

4 0
3 years ago
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