9514 1404 393
Answer:
use the appropriate calculator functions
Step-by-step explanation:
Log and Exp functions are transcendental functions. Each is defined by an infinite series. All modern scientific and graphing calculators have built-in algorithms for calculating these functions. The easiest way to calculate these function is to ...
make use of an electronic calculator
Detailed instructions for use will depend on the calculator.
_____
Alternatively, one can make use of tables. A typical table of log functions will be arranged to facilitate interpolation between table values when necessary. Again, the detailed instructions for using a particular table will depend on the table. The second attachment shows an example of a 4-decimal place log table.
Answer:
True
Step-by-step explanation:
![9x^2-12x +4 \\\\=(3x)^2 - 2\cdot 3x \cdot 2+2^2\\\\=(3x-2)^2](https://tex.z-dn.net/?f=9x%5E2-12x%20%2B4%20%5C%5C%5C%5C%3D%283x%29%5E2%20-%202%5Ccdot%203x%20%5Ccdot%202%2B2%5E2%5C%5C%5C%5C%3D%283x-2%29%5E2)
Answe
Given,
f(x) = 49 − x² from x = 1 to x = 7
n = 4
![\Delta x = \dfrac{7-1}{4}= 1.5](https://tex.z-dn.net/?f=%5CDelta%20x%20%3D%20%5Cdfrac%7B7-1%7D%7B4%7D%3D%201.5)
For x= 1
f(x₀) = 49 - 1^2 = 48
x = 2.5
f(x₁) = 42.75
x = 4
f(x₂) = 49 - 4^2 = 33
x = 5.5
f(x₃) = 49 - 5.5^2 = 18.75
x = 7
f(x₄) = 49 - 7^2 = 0
We have to evaluate the function on therigh hand point
![A = \Delta x [f(x_1)+f(x_2)+f(x_3)+f(x_4)]](https://tex.z-dn.net/?f=A%20%3D%20%5CDelta%20x%20%5Bf%28x_1%29%2Bf%28x_2%29%2Bf%28x_3%29%2Bf%28x_4%29%5D)
![A = 1.5 [42.75+33+18.75+0]](https://tex.z-dn.net/?f=A%20%3D%201.5%20%5B42.75%2B33%2B18.75%2B0%5D)
![A = 141.75](https://tex.z-dn.net/?f=A%20%3D%20141.75)
For Area for left hand sum
![A = \Delta x [f(x_0)+f(x_1)+f(x_2)+f(x_3)]](https://tex.z-dn.net/?f=A%20%3D%20%5CDelta%20x%20%5Bf%28x_0%29%2Bf%28x_1%29%2Bf%28x_2%29%2Bf%28x_3%29%5D)
![A = 1.5 [48+42.75+33+18.75]](https://tex.z-dn.net/?f=A%20%3D%201.5%20%5B48%2B42.75%2B33%2B18.75%5D)
![A =213.75](https://tex.z-dn.net/?f=A%20%3D213.75)
let's say the breakfast price was "x", so that's the 100%, and we know she gave 20% of that and that is 1.80.
so, 1.80 is 20%, and "x" is the 100%, what is "x"?
![\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 1.80&20\\ x&100 \end{array}\implies \cfrac{1.80}{x}=\cfrac{20}{100}\implies \cfrac{1.8}{x}=\cfrac{1}{5} \\\\\\ 9.0=x\implies 9=x](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccll%7D%20amount%26%5C%25%5C%5C%20%5Ccline%7B1-2%7D%201.80%2620%5C%5C%20x%26100%20%5Cend%7Barray%7D%5Cimplies%20%5Ccfrac%7B1.80%7D%7Bx%7D%3D%5Ccfrac%7B20%7D%7B100%7D%5Cimplies%20%5Ccfrac%7B1.8%7D%7Bx%7D%3D%5Ccfrac%7B1%7D%7B5%7D%20%5C%5C%5C%5C%5C%5C%209.0%3Dx%5Cimplies%209%3Dx)
Let's solve for x.
2
x
+
2
y
=
7
Step 1: Add -2y to both sides.
2
x
+
2
y
+
−
2
y
=
7
+
−
2
y
2
x
=
−
2
y
+
7
Step 2: Divide both sides by 2.
2
x
2
=
−
2
y
+
7
2
x
=
−
y
+
7
2
Let's solve for y.
2
x
+
2
y
=
7
Step 1: Add -2x to both sides.
2
x
+
2
y
+
−
2
x
=
7
+
−
2
x
2
y
=
−
2
x
+
7
Step 2: Divide both sides by 2.
2
y
2
=
−
2
x
+
7
2
y
=
−
x
+
7
2
Answer:
y
=
−
x
+
7
2