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2 years ago

15

How do you write mixed numbers as percents?

1 answer:

Sedbober [7]2 years ago

8 0

Convert the fraction part of the mixed number to a decimal,Divide the numerator by the denominator.

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Pls HELP meeee. My child needs some real help I I wish I would’ve took those college lessons.

Ksenya-84 [330]

I think the answer would be 75%, meaning that the orange juice would have a greater percentage of water.

3 0

2 years ago

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Find the value of x

iVinArrow [24]

Answer:

x = 121

Step-by-step explanation:

Let the measure of the altitude of the given triangle be h units.

By geometric mean theorem:

$h = \sqrt{23 \times x} \\ \\ h = \sqrt{23x} \\ \\ now \: by \: pythagors \: theorem \\ \\ {(x + 11)}^{2} = {h}^{2} + {x}^{2} \\ \\ \cancel{{x}^{2}} + 22x + 121 = {( \sqrt{23x} )}^{2} + \cancel{{x}^{2}} \\ \\ 22x + 121 = 23x \\ \\ 22x - 23x = - 121 \\ \\ - x = - 121 \\ \\ x = 121$

4 0

3 years ago

Calculate the sample mean and sample variance for the following frequency distribution of heart rates for a sample of American a

spin [16.1K]

Answer:

$Mean = 68.9$

$s^2 =18.1$ --- Variance

Step-by-step explanation:

Given

$\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

$x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5$

For 59 - 66

$x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5$

For 67 - 74

$x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5$

For 75 - 82

$x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5$

For 83 - 90

$x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5$

So, the table becomes:

$\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

The mean is then calculated as:

$Mean = \frac{\sum fx}{\sum f}$

$Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}$

$Mean = \frac{2547.5}{37}$

$Mean = 68.9$ -- approximated

Solving (b): The sample variance:

This is calculated as:

$s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}$

So, we have:

$s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}$

$s^2 =\frac{652.8}{36}$

$s^2 =18.1$ -- approximated

5 0

2 years ago

Jessica jogs on a path that is 25 km long to get to a park that is south of the jogging path. If it takes Jessica 2.5 hours then

GalinKa [24]

10 km per hour. hope this helps partially

6 0

3 years ago

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I need help!!!!!!!!!!!

notsponge [240]

Answer:

She teaches 6 classes

5 0

2 years ago