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iris [78.8K]
2 years ago
5

11 oranges cost 88p how much would 20 oranges cost?

Mathematics
2 answers:
lyudmila [28]2 years ago
6 0

Answer:

Wait actually here

Step-by-step explanation:

Download pptx
lubasha [3.4K]2 years ago
4 0

Answer:

5.0/5. 1.

Step-by-step explanation:

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Middle school Math!!!
makvit [3.9K]
Y=1x+2 (you don’t have to write the 1 in front of the x so you can write it as y=x+1)
6 0
3 years ago
Rewrite <img src="https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7Bx%5E%7B2%7D-x-12%20%7D%20%20and%20%5Cfrac%7B1%7D%7Bx%5E%7B2%7D-16%20%
gogolik [260]

Answer:

2(x+4)/(x+3)(x-4)(x+4) and 1(x+3)/(x+3)(x-4)(x+4)

Step-by-step explanation:

Factor x^2-x-12: (x+3)(x-4)

Factor x^2-16: (x+4)(x-4)

So, LCD would be (x+3)(x-4)(x+4)

Rewritten: 2(x+4)/(x+3)(x-4)(x+4) and 1(x+3)/(x+3)(x-4)(x+4)

I hope this helped and have a good rest of your day!

4 0
3 years ago
Read 2 more answers
A new centrifugal pump is being considered for an application involving the pumping of ammonia. The specification is that the fl
ollegr [7]

Answer:

from the t-distribution table, at df = 7 and t = 2.23

Lies p-values [ 0.05 and 0.025 ]

Hence;

0.025 < p-value < 0.05

Step-by-step explanation:

Given that;

x^{bar} = 6.5 gpm

μ = 5 gpm

n = eight runs = 8

standard deviation σ = 1.9 gpm

Test statistics;

t = (x^{bar} - μ) / \frac{s}{\sqrt{n} }

we substitute

t = (6.5 - 5) / \frac{1.9}{\sqrt{8} }

t = 1.5 / 0.67175

t = 2.23

the degree of freedom df = n-1 = 8 - 1

df = 7

Now, from the t-distribution table, at df = 7 and t = 2.23

Lies p-values [ 0.05 and 0.025 ]

Hence;

0.025 < p-value < 0.05

3 0
2 years ago
Suppose that the length of a phone call in minutes is an exponential random variable with parameter λ = 1/ 8. If someone arrives
Elis [28]

Answer:

a) P=0.535

b) P=0.204

c) P=0.286

Step-by-step explanation:

The exponential distribution is expressed as

F(x>t)=e^{-\lambda t}

In this example, λ=1/8=0.125 min⁻¹.

a) The probability of having to wait more than 5 minutes

F(x>5)=e^{-0.125*5}=e^{-0.625}=0.535

b) The probability of having to wait between 10 and 20 minutes

F(1020)=e^{-0.125*10}-e^{-0.125*20}\\\\F(10

c) The exponential distribution is memory-less, so it is independent of past events.

If you have waited 5 minutes, the probability of waiting more than 15 minutes in total is the same as the probability of waiting 15-5=10 minutes.

F(x>15|t^*=5)=F(x>15)/F(x>5)=\frac{e^{-0.125*15}}{e^{-0.125*5}}=e^{-0.125*(15-5)}\\\\ F(x>15|t^*=5)=e^{-0.125*(10)}=F(x>10)=0.286

5 0
3 years ago
What is 7,014,999,999 rounded to the nearest hundred thousand
Drupady [299]
I think the answer is: 7,015,000,000
5 0
2 years ago
Read 2 more answers
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