Y=1x+2 (you don’t have to write the 1 in front of the x so you can write it as y=x+1)
Answer:
2(x+4)/(x+3)(x-4)(x+4) and 1(x+3)/(x+3)(x-4)(x+4)
Step-by-step explanation:
Factor x^2-x-12: (x+3)(x-4)
Factor x^2-16: (x+4)(x-4)
So, LCD would be (x+3)(x-4)(x+4)
Rewritten: 2(x+4)/(x+3)(x-4)(x+4) and 1(x+3)/(x+3)(x-4)(x+4)
I hope this helped and have a good rest of your day!
Answer:
from the t-distribution table, at df = 7 and t = 2.23
Lies p-values [ 0.05 and 0.025 ]
Hence;
0.025 < p-value < 0.05
Step-by-step explanation:
Given that;
= 6.5 gpm
μ = 5 gpm
n = eight runs = 8
standard deviation σ = 1.9 gpm
Test statistics;
t = (
- μ) / 
we substitute
t = (6.5 - 5) / 
t = 1.5 / 0.67175
t = 2.23
the degree of freedom df = n-1 = 8 - 1
df = 7
Now, from the t-distribution table, at df = 7 and t = 2.23
Lies p-values [ 0.05 and 0.025 ]
Hence;
0.025 < p-value < 0.05
Answer:
a) P=0.535
b) P=0.204
c) P=0.286
Step-by-step explanation:
The exponential distribution is expressed as

In this example, λ=1/8=0.125 min⁻¹.
a) The probability of having to wait more than 5 minutes

b) The probability of having to wait between 10 and 20 minutes

c) The exponential distribution is memory-less, so it is independent of past events.
If you have waited 5 minutes, the probability of waiting more than 15 minutes in total is the same as the probability of waiting 15-5=10 minutes.

I think the answer is: 7,015,000,000