X^2-10x+16= 0
(x-8)(x-2)=0
x = 8 or 2
Answer:
+ 8x³ + 12x² - 16x + 4
Step-by-step explanation:
Given
[(x² + 4x) - 2 ]² ← simplify contents of bracket
= (x² + 4x - 2)² = (x² + 4x - 2)(x² + 4x - 2)
Each term in the second factor is multiplied by each term in the first factor, that is
x²(x² + 4x - 2) + 4x(x² + 4x - 2) - 2(x² + 4x - 2) ← distribute parenthesis
= + 4x³ - 2x² + 4x³ + 16x² - 8x - 2x² - 8x + 4 ← collect like terms
= + 8x³ + 12x² - 16x + 4
14). (Take π value as 22/7)
circumference = 66in
2πr = 66in
2×22/7×r = 66
r = 66×7/2×22
r = 21/2in
d = 2r => d = 2×21/2
therefore diameter of the circle = 21in
15). (Take π value as 3.14)
Circumference = 3.14m
2πr = 3.14m
2×3.14×r = 3.14
r = 3.14/3.14×2
r = 1/2m
Therefore the radius of the circle = 0.5m
16). (Take π value as 22/7)
Circumference = 33km
2πr = 33km
2×22/7×r = 33
r = 33×7/2×22
r = 21/4
d = 2r
d = 2×21/4
d = 21/2km
Therefore the diameter of the circle = 10.5km
I believe it is false because it only passes through the y-axis not the x-axis.
