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iris [78.8K]
2 years ago
5

11 oranges cost 88p how much would 20 oranges cost?

Mathematics
2 answers:
lyudmila [28]2 years ago
6 0

Answer:

Wait actually here

Step-by-step explanation:

Download pptx
lubasha [3.4K]2 years ago
4 0

Answer:

5.0/5. 1.

Step-by-step explanation:

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PLEASE HELP 50 POINTS
Arada [10]

Answer:

im leaning on parallelogram

Step-by-step explanation:

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3 years ago
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1 substitute p=5, q=7, r = -2
lora16 [44]

1.

a.) 2q + 5r

2(7) + 5(-2)

14 - 10 = 4


b.) 3(p + 6) + q + r     Plug in the numbers

3(5 + 6) + 7 - 2   Solve inside the parentheses first

3(11) + 7 - 2

33 + 5 = 38


2.

a.) m(3m + 4n)

2(3(2) + 4(3))

2(6 + 12)

2(18) = 36


b.) n²(m + p²)

(3)²(2 + (-5)²)

9(2 + 25)

9(27) = 243


c.) 3m(8 + n) + n²

3(2) (8 + 3) + 3²

6(11) + 9

66 + 9 = 75

3 0
3 years ago
What do I do in the right side column
KIM [24]
The same thing to the other side
8 0
3 years ago
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In a certain section of Southern California, the distribution of monthly rent for a one-bedroom apartment has a mean of $2,275 a
KATRIN_1 [288]

Answer:

100% probability of selecting a sample of 65 one-bedroom apartments and finding the mean to be at least $2,095 per month

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of $2,275 and a standard deviation of $290.

This means that \mu = 2275, \sigma = 290

Sample of 65:

This means that n = 65, s = \frac{290}{\sqrt{65}}

Finding the mean to be at least $2,095 per month

This is 1 subtracted by the p-value of Z when X = 2095. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{2095 - 2275}{\frac{290}{\sqrt{65}}}

Z = -5

Z = -5 has a p-value of 0.

1 - 0 = 1

100% probability of selecting a sample of 65 one-bedroom apartments and finding the mean to be at least $2,095 per month

7 0
3 years ago
What is the approximate estimation for 29.942 + 13.433
Nana76 [90]

Answer:

the answer would be it is approximately <u>4</u><u>3</u><u>.</u><u>8</u><u>5</u>

<u>(</u><u>did </u><u>addition</u><u>)</u>

6 0
3 years ago
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