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jenyasd209 [6]
4 years ago
13

The population of a town increased by 15% in 2016, and decreased by 5% in 2017. If the population of the town was 60,000 in the

beginning of 2016, then what was it at the end of 2017?
Mathematics
1 answer:
nikdorinn [45]4 years ago
3 0

Answer:

The population of the town at the end of 2017 was 65,550.

Step-by-step explanation:

The population of the town was 60,000 in the beginning of 2016.

In 2016, the total population is increased by 15%.

60,000\times\frac{15}{100}=9000

Therefore the population is increased by 9000 and the population of the town at the end of 2016 was

60,000+9000=69,000

In 2017, the total population is decreased by 5%.

69,000\times\frac{5}{100}=3450

Therefore the population is decreased by 3450 and the population of the town at the end of 2017 was

69,000-3450=65,500

Therefore the population of the town at the end of 2017 was 65,550.

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Step-by-step explanation:

sin(angle)=\frac{opposite}{hypotenuse}

cos(angle)=\frac{adjacent}{hypotenuse}

tan(angle)=\frac{opposite}{adjacent}

  • The cosine of an angle is equal to the side adjacent to the angle over the hypotenuse, the longest side.
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cos(V)=\frac{39}{hypotenuse}

  • We need to find the hypotenuse of this triangle. This is relativly easy to do with a right triangle; we can just use the Pythagorean Theorem.
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a^2+b^2=c^2\\(39)^2+(80)^2=c^2\\1521+6400=c^2\\c=\sqrt{7921} \\c=89

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