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Brut [27]
3 years ago
14

What is rounding to the whole percent

Mathematics
1 answer:
ratelena [41]3 years ago
8 0
To round a number to the nearest whole number, you have to look at the first digit after the decimal point. If this digit is less than 5 (1, 2, 3, 4) we don't have to do anything, but if the digit is 5 or greater (5, 6, 7, 8, 9) we must round up.
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Point L is on line segment KM . Given KM = 5x + 10 , LM = 4x , and KL = 3x , determine the numerical length of KL
zalisa [80]

Answer:15

I know Bc I got it wrong that was the answer

6 0
3 years ago
8 5/6 + 2 3/4 +__=14 this is fractions so the answer should be a fraction please help
Mariulka [41]

Answer:

2 5/12

Step-by-step explanation:

8 5/6 + 2 3/4 = 8 10/12 + 2 9/12  =  10 19/12  =  10 + 1 7/12  =  11 7/12

13 12/12 - 11 7/12 = 2 5/12

3 0
3 years ago
Picture thanks a lot
kobusy [5.1K]
2.8 is the correct answer :)
7 0
3 years ago
Assume V and W are​ finite-dimensional vector spaces and T is a linear transformation from V to​ W, T: Upper V right arrow Upper
scZoUnD [109]

Answer:

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

Step-by-step explanation:

Let B = {v_1 ,v_2,..., v_p} be a basis of H, that is dim H = p and for any v ∈ H there are scalars c_1 , c_2, c_p, such that v = c_1*v_1 + c_2*v_2 +....+ C_p*V_p It follows that  

T(v) = T(c_1*v_1 + c_2v_2 + ••• + c_pV_p) = c_1T(v_1) +c_2T(v_2) + c_pT(v_p)

so T(H) is spanned by p vectors T(v_1),T(v_2), T(v_p). It is enough to prove that these vectors are linearly independent. It will imply that the vectors form a basis of T(H), and thus dim T(H) = p = dim H.  

Assume in contrary that T(v_1 ), T(v_2), T(v_p) are linearly dependent, that is there are scalars c_1, c_2, c_p not all zeros, such that  

c_1T(v_1) + c_2T(v_2) +.... + c_pT(v_p) = 0

T(c_1v_1) + T(c_2v_2) +.... + T(c_pv_p) = 0

T(c_1v_1+ c_2v_2 ... c_pv_p) = 0  

But also T(0) = 0 and since T is one-to-one, it follows that c_1v_1 + c_2v_2 +.... + c_pv_p = O.

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

8 0
3 years ago
Please help very easy.
adelina 88 [10]

Answer:

1/2 IN FRACTION FORM

0.5 IN DECIMAL FORM

Step-by-step explanation:

5 0
3 years ago
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