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3 years ago

WILL MARK BRAINLIEST IF CORRECT!!!!!!!!!!! :) (IMAGE ATTACHED)

Mathematics

2 answers:

Llana [10]3 years ago

8 0

Answer:

Step-by-step explanation:

just did it

Gnom [1K]3 years ago

7 0

Answer:

$\huge\boxed{Option \ B: 5\sqrt[3]{10} + 4\sqrt[3]{10} }$

Step-by-step explanation:

$\sf 9\sqrt[3]{10} \\We \ can \ split \ 9 \ into\ 5 \ and \ 4\\(5 + 4)\sqrt[3]{10} \\Applying distributive property\\5\sqrt[3]{10} + 4\sqrt[3]{10}$

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A professor of women's studies is interested in determining if stress affects the menstrual cycle. Ten women are randomly sample

BabaBlast [244]

Answer:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

$t=\frac{(20.4 -27.6)-(0)}{\sqrt{\frac{2.074^2}{5}}+\frac{2.702^2}{5}}=-4.73$

$df=5+5-2=8$

$t_{crit}=\pm 2.306$

Reject H0: stress affects the menstrual cycle

Step-by-step explanation:

The statistic is given by the following formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{s^2_2}{n_2}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2 \neq 0$

Our notation on this case :

$n_1 =5$ represent the sample size for group 1

$n_2 =2$ represent the sample size for group 2

Tha data given is:

Group 1 (High stress) : 20,23,18,19,22

Group 2 (Relatively stress free): 26,31,25,26,30

We can calculate the sample mean and the sample deviation with the following formulas:

$\bar X =\frac{\sum_{i=1}^n x_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}$

$\bar X_1 =20.4$ represent the sample mean for the group 1

$\bar X_2 =27.6$ represent the sample mean for the group 2

$s_1=2.074$ represent the sample standard deviation for group 1

$s_2=2.702$ represent the sample standard deviation for group 2

And now we can calculate the statistic:

$t=\frac{(20.4 -27.6)-(0)}{\sqrt{\frac{2.074^2}{5}}+\frac{2.702^2}{5}}=-4.73$

Now we can calculate the degrees of freedom given by:

$df=5+5-2=8$

Now we can calculate the critical value since the confidence is 95% the value for the significance would be $\alpha=1-0.95=0.05$ and the value for $\alpha/2 =0.025$ and if we find a critical value on th t distribution with 8 degrees of freedom that accumulates 0.025 of the area on each tail we got $t_{crit}=\pm 2.306$

Since our calculated value is lower than the critical value, we have enough evidence to reject the null hypothesis. And makes sense say that the difference between the two means are different at 5% of significance.

Reject H0: stress affects the menstrual cycle

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3 years ago

What is 1/2 of 1/6 = <br> as a fraction

aleksandr82 [10.1K]

Answer: 1/12
Step by step: it’s simple really.

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3 years ago

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Ali currently has $25. He is going to start saving $5 every week. Ali's Savings Function Rule: y = 5x + 25

makvit [3.9K]

Answer:

x-intercept: (-5,0)

y-intercept (0,25)

or in standard form 5x - y = -25

Step-by-step explanation:

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3 years ago

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Harrizon [31]

Answer:

lana

Step-by-step explanation:

she saves 100$ in 2weeks more than 94

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3 years ago

Determine the relationship described in each table.

densk [106]

For the first table, the y-values are not equally spaced and the ratios of y are not the same, but by plotting them and observing the graph that results, it looks like the points lie on an exponential curve. The second table is linear because when x changes by 1, y changes by 4. The third table is a quadratic model because even if the first differences of y are not the same, the second differences of y have the same value of 8. The fourth table is exponential because the ratio of y-values is 2, which is the same between each set of numbers.

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3 years ago

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