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UkoKoshka [18]
3 years ago
5

No links plz real answers

Mathematics
1 answer:
velikii [3]3 years ago
4 0

Answer:

That answer would be 4 because 26+4 is 30 it should be right

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What is 2/5x3/4 in most reduced from
Gnoma [55]

Answer:

3/

10

= 0.3

Step-by-step explanation:

Multiple: 2/5

* 3/4

= 2 · 3/5· 4

= 6/20

= 3 · 2/10 ·  2

= 3/10

Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(6, 20) = 2. In the following intermediate step, cancel by a common factor of 2 gives 3/

10

.

In other words - two fifths multiplied by three quarters = three tenths.

3 0
3 years ago
Read 2 more answers
A city has a population of 245,600 which is 110% of the population from the previous year. What was the population the previous
MrMuchimi
<h2>Answer:</h2><h2>The city population last year = 2233 approximately</h2>

Step-by-step explanation:

The current population of the city = 245,600

Rate of increase = 110 %

The population in previous year = ?

Let x be the population of previous year

x(110%) = 245600

x = \frac{245600}{110}

= 2232.7

The city population last year = 2233 approximately

4 0
3 years ago
If m stands for the number, which best represents the following phrase? The product of eight and a number, decreased by ten *
Whitepunk [10]

Answer:

C

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The sum of three consecutive even integers is 270. What is the biggest integer?
saveliy_v [14]
3 consecutive even integers.....x, x + 2, and x + 4

x + x + 2 + x + 4 = 270
3x + 6 = 270
3x = 270 - 6
3x = 264
x = 264/3
x = 88

x + 2 = 88 + 2 = 90
x + 4 = 88 + 4 = 92 <=== the biggest integer
3 0
4 years ago
Read 2 more answers
Sin(a)+sin(b)=sqrt(5/3) and cos(a)+cos(b)=1. Compute cos(a-b).
Reil [10]
Square both given expressions and add them together. Make use of trig identities.

&nbsp; (sin(a) +sin(b))^2 = sin(a)^2 +2sin(a)sin(b) +sin(b)^2 = 5/3

&nbsp; (cos(a) +cos(b))^2 = cos(a)^2 +2cos(a)cos(b) +cos(b)^2 = 1

Adding, we have
&nbsp; sin(a)^2 +cos(a^2) +2(cos(a)cos(b) +sin(a)sin(b)) +sin(b)^2 +cos(b)^2 = 2 2/3

Of course, the first and last pairs of terms are 1 and 1, and the middle product is 2cos(a-b), so you have
&nbsp; 1 + 2cos(a-b) +1 = 2 2/3
&nbsp; cos(a-b) = 1/3
6 0
3 years ago
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