Question

What is the value of A when we rewrite (1/8)^x + (1/8)^x-2 as A x (1/8)^x

Answer 1

Answer:

-63

Step-by-step explanation:

Given the expression:

$(1/8)^x + (1/8)^{x-2}$

Using the law of indices, this can be written as:

$(\frac{1}{8})^x-(\frac{1}{8} )^x * (\frac{1}{8})^{-2}\\(\frac{1}{8})^x (1-(\frac{1}{8})^{-2})\\(\frac{1}{8})^x(1-8^2)\\(\frac{1}{8})^x(-63)\\-63(\frac{1}{8})^x$

This shows that the value of A is -63