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GalinKa [24]
3 years ago
8

Solve the inequality 4x-7<5​

Mathematics
1 answer:
aev [14]3 years ago
8 0

Answer:

4x-7 < 5

4x-7+7 < 5+7

4x/4 < 12/4

x < 3

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Determine whether a figure with the given vertices is a rectangle using the Distance Formula.
Alex Ar [27]

Answer:

Yes; Opposite sides are congruent, and diagonals are congruent.

Step-by-step explanation:

we have

A(4, -7), B(4, -2), C(0, -2), D(0, -7)

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the length of the sides

<u><em>Find the distance AB</em></u>

substitute the values

d=\sqrt{(-2+7)^{2}+(4-4)^{2}}

d=\sqrt{(5)^{2}+(0)^{2}}

AB=5\ units

<u><em>Find the distance BC</em></u>

substitute the values

d=\sqrt{(-2+2)^{2}+(0-4)^{2}}

d=\sqrt{(0)^{2}+(-4)^{2}}

BC=4\ units

<u><em>Find the distance CD</em></u>

substitute the values

d=\sqrt{(-7+2)^{2}+(0-0)^{2}}

d=\sqrt{(-5)^{2}+(0)^{2}}

CD=5\ units

<u><em>Find the distance AD</em></u>

substitute the values

d=\sqrt{(-7+7)^{2}+(0-4)^{2}}

d=\sqrt{(0)^{2}+(-4)^{2}}

AD=4\ units

Compare the length sides

AB=CD

BC=AD

therefore

Opposite sides are congruent

step 2

Find the length of the diagonals

<u><em>Find the distance AC</em></u>

substitute the values

d=\sqrt{(-2+7)^{2}+(0-4)^{2}}

d=\sqrt{(5)^{2}+(-4)^{2}}

AC=\sqrt{41}\ units

<u><em>Find the distance BD</em></u>

substitute the values

d=\sqrt{(-7+2)^{2}+(0-4)^{2}}

d=\sqrt{(-5)^{2}+(-4)^{2}}

BD=\sqrt{41}\ units

Compare the length of the diagonals

AC=BD

therefore

Diagonals are congruent

The figure is a rectangle, because Opposite sides are congruent, and diagonals are congruent

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4 years ago
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