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Setler [38]
3 years ago
8

I need the help!!! I don't rember how to do this. Explain if u can.

Mathematics
1 answer:
-Dominant- [34]3 years ago
5 0

1. 3/2x+4=-9

3/2x=-13 (Combine like terms)

(divide both sides by 3/2)

x=-26/3 or -8 2/3

2. 2(3x-7)+4x=26

6x-14+4x=26 (distribute the 2)

10x-14=26 (combine like terms)

10x=40 (add 14 to both sides)

(Divide both sides by 10)

x=4

3. 4-3x=5-6x-7

4-3x=-2-6x (combine like terms)

4=-2-3x (add 3x to both sides)

6=-3x (add 2 to both sides)

(divide both sides by -3)

x=-2

4. 11y-3=5

11y=8 (combine like terms)

(divide both sides by 11)

y=8/11

5. 5-3x<14

-3x<9 (combine like terms)

(divide both sides by -3) (flip the < to > because youre dividing by a negative)

x >-3 The graph is a vertical (up and down) line at -3... it is a dashed line and shade towards the postitive numbers

6. x/x+2=3/7

7x=3(x+2) (cross multiply)

7x=3x+6 (distribute the 3)

4x=6 (combine like terms)

(divide both sides by 4)

x=6/4 or 1 2/4 or 1 1/2

7. 1.5/36=x/24 (instead of using 1 1/2, I used 1.5 since it is easier to work with)

36x=36 (cross multiply)

(divide both sides by 36)

X=1

8. y=2x+5 3x-2y=10 (this is a substitution problem)

3x-2(2x+5)=10 (plug in y=2x+5 in the second equation)

3x-4x-10=10 (distribute the -2)

-1x=20 (combine like terms and add 10 to both sides)

(divide each side by -1)

x=-20

(plug in -20 for either equation... I used y=2x+5)

y=2(-20)+5

y=-40+5 (distribute the 2)

y=-35

10. 6x-3y=11 6x+3y=17 (this is an elmination problem) (-3y & +3y cancle each other out so they will not be in the following steps until the end)

6x=11 +6x=17

12x=28 (combine the X's and 11+17)

(divide both sides by 12)

X= 7/3

(plug in 7/3 in either equation... i used 6x+3y=17)

6(7/3)+3y=17 (plug in 7/3 for x)

14+3y=17 (distribute)

3y=3 (combine like terms)

(divide both sides by 3)

y=1

10. 3x+5y=22 4x+3y=11 (since you can't eliminate here, you have to multiply both equations by a number to be able to... I multiplied the first equation by -3 and the second by 5. I'll be starting at the point after the multiplication)

-9x-15y=-66 20x+15y=55 (-15y & +15y cancle out)

-9x=-66 20x=55

11x=-11 (combine like terms)

(divide both sides by 11)

x=-1

(to find the value of y, plug in -1 into either equation and solve... i used 3x+5y=22)

3(-1)+5y=22 (plug in)

-3+5y=22 (distribute)

5y=25 (combine like terms)

(divide both sides)

y=5

11. n^2+3n-12=6

n^2+3n-18=0 (subtract 6 from both sides)

(n+3)(n-6) (to solve these, set them equal to 0 and get n alone)

n= -3, n=6

12. 2n^2+5n+2

(2n^2+n)+(4n+2)

n(2n+1)+2(2n+1)

(2n+1)(n+2)

MORE ANSWERS TO COME... STILL NEED TO SOLVE THEM

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Answer:

M: (2,-2)

N: (1,2)

O: (2,-4)

P: (5, -2)

Step-by-step explanation:

What you would do is find out where the two lines intercross. The 2 right quadrants are positive. The two left are negative. Count the lines and figure out the ordered pair. X is left and right, y is up and down. For example, if you were given a ordered pair, (4,-2) you would go up four, and left 2.

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3 years ago
25x^2+1=5 quadratic
Olenka [21]
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25x² + 1 - 5 = 0

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(5x)² - (2)² = 0

(5x - 2)(5x + 2) = 0

5x - 2 = 0    or          5x + 2 = 0

5x = 0 + 2                5x = 0 - 2

5x = 2                      5x = -2 

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3 0
3 years ago
Los puntajes obtenidos por un grupo de alumnos en un examen de 10 puntos son 3,5,2,6,5,9,5,2,8,6. Para saber el puntaje máximo q
Vikentia [17]

Answer:

Para saber el puntaje máximo que obtuvo el 75% de los alumnos se debe calcular el tercer cuartil.

Step-by-step explanation:

Los Cuantiles (cuartiles, deciles, percentiles) son medidas de localización cuya  función es informar del valor de la variable que ocupará la posición (en tanto por  cien) que interese respecto de todo el conjunto de variables.

Los cuartiles son medidas estadísticas de posición que tienen la  propiedad de dividir la serie estadística en cuatro grupos de números iguales de  términos.

El primer cuartil o cuartil inferior es aquel valor de la variable tal que la cuarta parte (25%) de las observaciones son inferiores o iguales a él, y el resto (75%) es superior o igual. El segundo cuartil es la mediana, ya que se trata del valor localizado en la mitad de la distribución. Finalmente, el tercer cuartil o cuartil superior es un valor tal que las tres cuartas partes de las observaciones son inferiores o iguales a él.

En otras palabras, el primer cuartil Q1, es el valor en el cual o por debajo del cual queda aproximadamente un cuarto (25%) de todos los valores de la sucesión (ordenada); El segundo cuartil Q2 es el valor por debajo del cual queda el 50% de los datos (Mediana), el tercer cuartil Q3 es el valor por debajo del cual quedan las tres cuartas partes (75%) de los datos. Es decir, Q1, Q2 y Q3 determinan los valores correspondientes al 25%, al 50% y al 75% de los datos respectivamente. Q2 coincide con la mediana.

<u><em>Para saber el puntaje máximo que obtuvo el 75% de los alumnos se debe calcular el tercer cuartil.</em></u>

<u><em></em></u>

5 0
3 years ago
PLS HELP I NEED IT I will give u points
loris [4]

Answer:

15b

Step-by-step explanation:

3x5

3 0
3 years ago
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