The equation which could be used to find the length of the hypothenuse is; 5 squared + 8 squared = c squared.
<h3>Which equation could be used to find the length of the hypothenuse?.</h3>
It follows from the task content that the equation which could be used to find the length of the third side be determined.
Hence, since it follows from Pythagoras theorem that the square of the hypothenuse is equivalent to the sum of the squares of the two other sides of a right triangle.
Hence, the required equation is; 5 squared + 8 squared = c squared.
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Answer:
129.5 cm²
Step-by-step explanation:
The area (A) of a trapezoid is calculated as
A = 
h(a + b)
where h is the height and a, b the parallel bases
Here h = 7, a = 15 and b = 22 , thus
A = × 7 × (15 + 22)
= 0.5 × 7 × 37
= 129.5
Answer:
3( y - 2) + 2y =9
Step-by-step explanation:
It equals 3.
Answer:
C. 4x^3 - 14x^2y + 14xy^2 - 4y^3
Step-by-step explanation:
Given:
Product of 2x^2 – 3xy + y^2 and 2x – 4y
Product means multiplication
(2x^2 – 3xy + y^2) (2x – 4y)
Open the bracket
= 4x^3 - 8x^2y - 6x^2y + 12xy^2 + 2xy^2 - 4y^3
Simplify the like terms
= 4x^3 - 14x^2y + 14xy^2 - 4y^3
The answer is
C. 4x^3 - 14x^2y + 14xy^2 - 4y^3
