$2 \times x \times \frac{1}{x} = 2 \\ {x}^{2} + {y }^{2} + 2xy = {(x + y)}^{2} \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2 = {(x + \frac{1}{x} })^{2} = {3}^{2} = 9$

8 0

2 years ago

What is the standard deviation of the following data set?

tia_tia [17]

Answer:

D. 14.32

Step-by-step explanation:

The formula for standard deviation is:

$SD = \sqrt{\frac{\sum | x-\mu|^2}{N}}$

The mean μ is 33.

The (x minus μ) squared are 361, 49, 49, 361 respectively.

So that the SD = $\sqrt{\frac{820}{4}} \approx 14.31782...$

4 0

2 years ago

Bob is throwing a party. He has 22 pints of soda. At the end of the party, there are 8 pints of soda. How many cups of soda were

Lady_Fox [76]

28 cups of soda were drank at the party

7 0

2 years ago

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I WILL MARK BRAINLIST!!

Soloha48 [4]

Answer:

For $(2x^2 + 8x - 8)$ , the group is CLOSED as it a polynomial.

Step-by-step explanation:

Here, the given polynomials are:

$P(x)=(5x^2+2x-6)\\Q(x)=(3x^2-6x+2)$

Now, a group G is said to be CLOSED UNDER SUBTRACTION if,

a and b are he elements of G ⇒ (a-b) is ALSO AN ELEMENT of G

Now, here:

$R(x) = P(x) - Q(x) = (5x^2+2x-6) - (3x^2-6x+2) = (2x^2 + 8x - 8)$

or, $R(x) = (2x^2 + 8x - 8)$

Also, R(x) is a POLYNOMIAL.

So, R(x) is an Element of group G.

So, the set G of polynomials.

Hence, for the polynomial $(2x^2 + 8x - 8)$ , it will be a polynomial the group is CLOSED.

3 0

3 years ago

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