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2 years ago

Is the expression 3(x+1 1/2)-3 equivalent to 3x+ 1 1/2

Mathematics

1 answer:

stira [4]2 years ago

7 0

Answer:

Yes

Step-by-step explanation:

3(x+5.50)-3

3x+16.50)-3

-3(3x+16.50)

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1. Explain how you could break apart<br>an array to find 6 X 7. Draw an array<br>to show your work.

matrenka [14]

6x7=42 so divide 42 divided by 7 equals 6

4 0

2 years ago

Help anyone can help me do this question,I will mark brainlest.

postnew [5]

Answer:

Step-by-step explanation:

7 0

2 years ago

I need help on all of these

lord [1]

well #7 is a solution.

y= 9x (4,36)

9 times 4 = 36

36/9=4

so the ordered pair is a solution.

y=3x-5 (7,16)

3 times 7 -5= 16

so once again the ordered pair is a solution.

Hoped this helped.

5 0

2 years ago

Compare 5/6 and 1/3 using the benchmark fraction 1/2

fenix001 [56]

Answer:

Step-by-step explanation:

Denominators: 6 is 2 times more than 3

Make them common fractions

5/6 and 2/6

They are 3/6 apart, or 1/2 apart

8 0

3 years ago

Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g

SpyIntel [72]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see $\bf f(x)=\sqrt{x}\qquad 
\begin{array}{llll}
g(x)=&\sqrt{0.5x}\\
&\quad \uparrow \\
&\quad B
\end{array}$

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.

8 0

2 years ago

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