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MAXImum [283]
2 years ago
5

-3(-7 - x) = 1/2 (x + 2)

Mathematics
2 answers:
xz_007 [3.2K]2 years ago
8 0
The answer is - X= -8
maw [93]2 years ago
3 0

Answer:

x=-8

Steps:

Simplify-

−3(−7−x)= x+2/2

Simplify-

−3(−7−x)= 1+ x/2

Multiply both sides by 2-

−6(−7−x)=2+x

Expand-

42+6x=2+x

Subtract 2 from both sides-

42+6x−2=x

Simplify-

6x+40=x

Subtract 6x from both sides-

40=x−6x

Simplify-

40=−5x

Divide-

-40/5=x

Simplify-

-8=x

Switch sides-

x=-8

I believe this is correct, if not let me know and I will fix it.

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Answer:

x = 95

Step-by-step explanation:

Using the rule of logarithms

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Given

log_{5}(x + 30) = 3, then

x + 30 = 5³ = 125 ( subtract 30 from both sides )

x = 95

7 0
3 years ago
Cot^2x/cscx-1=1+sinx/sinx
KATRIN_1 [288]
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5 0
3 years ago
(85 x 255) / 289 + 15 - 70 =
ANEK [815]
I do believe its twenty

5 0
3 years ago
Read 2 more answers
Twelve percent of the population is left handed. Approximate the probability that there are at least 20 left-handers in a school
DochEvi [55]

Answer:

Step-by-step explanation:

We would assume a binomial distribution for the handedness of the population. Let x be a random variable representing the type of handedness in the population. The probability of success, p is that a randomly chosen person is left handed only. Then probability of failure is that a chosen person is not left handed only(right handed only or both).

p = 12/100 = 0.12

number of success, x = 20

n = 200

the probability that there are at least 20 left-handers is expressed as P(x ≥ 20)

From the binomial probability calculator,

P(x ≥ 20) = 0.84

8 0
3 years ago
Find the distance between the points of intersection of the graphs of the functions.
Viefleur [7K]

Answer:

Find the value of x and y in coordinate form, that'll be the point of intersection.

Question 1

{ \rm{y =  {x}^{2} - 3x + 4 }} \\ { \boxed{ \tt{but \: y = x + 1 \: }}} \\  \\ { \rm{(x + 1) =  {x}^{2} - 3x + 4 }} \\  \\ { \rm{ {x}^{2} - 4x + 3 = 0 }} \\  \\ { \rm{(x - 3)(x - 1) = 0}} \\  \\ { \boxed{ \rm{x_{1} = 3 \:  \: and \:  \: x _{2}  = 1}}} \\  \\ { \boxed{ \tt{remember \: y = x + 1}}} \\  \\ { \rm{y _{1} = 4 \:  \: and \:  \: y _{2}  = 2 }}

Therefore, points of intersection are two

Answer: <u> </u><u>(</u><u>3</u><u>,</u><u> </u><u>4</u><u>)</u><u> </u><u>and</u><u> </u><u>(</u><u>1</u><u>,</u><u> </u><u>2</u><u>)</u>

Question 2:

Following the steps as in question 1

{ \rm{y =  {x}^{2}  - 4}} \\  \\{ \rm{2x - 4 =  {x}^{2}  - 4}} \\  \\ { \rm{ {x}^{2} = 2x }} \\  \\ { \boxed{ \rm{x = 2}}} \\ { \tt{remember : \: y = 2x - 4 }} \\ { \boxed{ \rm{y = 0}}}

Answer: <u>(2, 0)</u>

7 0
2 years ago
Read 2 more answers
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