Answer:
For a scaler variable, the Gaussian distribution has a probability density function of
p(x |µ, σ² ) = N(x; µ, σ² ) = 1 / 2π×![e^{\frac{-(x-u)^{2}}{2s^{2} } }](https://tex.z-dn.net/?f=e%5E%7B%5Cfrac%7B-%28x-u%29%5E%7B2%7D%7D%7B2s%5E%7B2%7D%20%7D%20%20%7D)
The term will have a maximum value at the top of the slope of the 1-D Gaussian distribution curve that is when exp(0) =1 or when x = µ
Step-by-step explanation:
Gaussian distributions have similar shape, with the mean controlling the location and the variance controls the dispersion
From the graph of the probability distribution function it is seen that the the peak is the point at which the slope = 0, where µ = 0 and σ² = 1 then solution for the peak = exponential function = 0 or x = µ
Answer:
Angle of A = 90 degree-62 degree = 28 degree.
Step-by-step explanation:
tan (62) = opposite / adjacent = 10 / a ---> a = 10/tan (62) = 10/ 1.88 = 5.319
cos (62) = a/c --->c = a/cos (62) = 5.319 / 0.47 = 5.3 / 0.47 = 11.3
or another way.
sin (62) = 10 /c ---> c = 10/ sin (62) = 10 / 0.88 = 11.3
So Angle of A = 28 degree.
a = 5. 3
c = 11.3.
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Answer:
3ft
Step-by-step explanation:
We are given that
Height of lamp, h=12ft
Height of shadow, l=6ft
Height of shadow of hydrant, l'=1.5ft
Let height of hydrant=h'
We have to find the height of fire hydrant.
All right triangles are similar
When two triangles are similar then, the ratio of their corresponding sides are equal.
Using the property
![\frac{h}{h'}=\frac{l}{l'}](https://tex.z-dn.net/?f=%5Cfrac%7Bh%7D%7Bh%27%7D%3D%5Cfrac%7Bl%7D%7Bl%27%7D)
![\frac{12}{h'}=\frac{6}{1.5}](https://tex.z-dn.net/?f=%5Cfrac%7B12%7D%7Bh%27%7D%3D%5Cfrac%7B6%7D%7B1.5%7D)
![h'=\frac{12\times 1.5}{6}](https://tex.z-dn.net/?f=h%27%3D%5Cfrac%7B12%5Ctimes%201.5%7D%7B6%7D)
ft
Hence, the height of fire hydrant=3 ft