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Montano1993 [528]

3 years ago

9

A number is equal to three times a smaller number also the sum of the smaller number and four is the larger number the situation

is right on the corner playing below where X represents the smaller number and why represents the larger number

1 answer:

djyliett [7]3 years ago

7 0

Answer:

I'm assuming that "why" is not part of this problem so this too is not answerable

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Please answer ASAP and if you do you will get Brainliest. Catherine buys a gallon of ice cream from the store. After taking it h

rodikova [14]

Answer:

Catherine's sister ate 2/15 gallons of the ice cream.

$\displaystyle \frac{2}{15}$ .

Step-by-step explanation:

Let $x$ be the amount of ice cream that Catherine's sister ate, in gallons.

Original amount: 1 gallon.

What Catherine ate: $\displaystyle \frac{1}{5}$ gallons.
What Catherine's sister ate is assumed to be $x$ gallons.

What's left: $\displaystyle \frac{2}{3}$ gallons.

Consider the relationship:

$\text{Original amount - What Catherine ate - What Catherine's Sister ate}\\ =\text{ What's left.}$ .

That is:

$\displaystyle 1- \frac{1}{5} - x = \frac{2}{3}$ .

Add $x$ to both sides of this equation:

$\displaystyle 1 - \frac{1}{5} = \frac{2}{3} +x$

Substract $\displaystyle \frac{2}{3}$ from both sides:

$\displaystyle 1 - \frac{1}{5} - \frac{2}{3} = x$ .

Convert the denominator of all three numbers on the left-hand side to $3 \times 5 = 15$

$\displaystyle \frac{15}{15} - \frac{3}{15} - \frac{10}{15} = x$ .

$\displaystyle x = \frac{2}{15}$ .

In other words, Catherine's sister ate $\displaystyle \frac{2}{15}$ gallons of the ice cream.

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Juli2301 [7.4K]

Answer:

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Step-by-step explanation:

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2 years ago

If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95% confident that the d

katen-ka-za [31]

Answer:

We need a sample size of least 119

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Sample size needed

At least n, in which n is found when $M = 0.09$

We don't know the proportion, so we use $\pi = 0.5$ , which is when we would need the largest sample size.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.09 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.09\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.09}$

$(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.09})^{2}$

$n = 118.6$

Rounding up

We need a sample size of least 119

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Well Emily, i believe it is B.

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Alexxx [7]

Answer:

Step-by-step explanation:

A

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