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3 years ago

10

The graph models the linear relationship between the charge for a trip and the

1 answer:

mamaluj [8]3 years ago

4 0

Answer:

Number 3/ letter C

Step-by-step explanation:

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3 years ago

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3 years ago

The radius of a semicircle is 3 kilometres. What is the semicircle's perimeter?

alina1380 [7]

Answer:

In terms of Pi: $3\pi + 6$ km

Exact value (rounded): 15.42477 km

Approximated (3.14): 15.42 km

Step-by-step explanation:

Hello!

A semicircle's perimeter can be found using the formula: $P = \pi r + 2r$

We can plug in the values to solve for the perimeter.

<h3>Solve</h3>

$P = \pi r + 2r$
$P = \pi(3)+ 2(3)$
$P = 3\pi + 6$

In terms of Pi, it is $3\pi + 6$ ,

Exact value of Pi, it is 15.42477

Approximation of Pi (3.14), it is = 15.42

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2 years ago

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4 years ago

Read 2 more answers

Suppose that the number of customers that enter a bank in an hour is a Poisson random variable, and suppose that P(X = 0) = 0.09

Ksju [112]

Answer:

$E(X) = V(X) = 2.41$

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

In the Poisson distribution, the mean is the same as the variance.

P(X = 0) = 0.09

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-\mu}*\mu^{0}}{(0)!} = e^{-\mu}$

So

$e^{-\mu} = 0.09$

We apply ln to both sides, which is the inverse operation of the exponential.

So

$\ln{e^{-\mu}} = \ln{0.09}$

$-\mu = -2.41$

Multiplying by -1

$\mu = 2.41$

So

$E(X) = V(X) = 2.41$

8 0

3 years ago