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Zinaida [17]
3 years ago
8

one of sam's best customer spend 250.00 each month in sam's shop. She say that is roughly 5% of her monthly income. How much doe

s she make each month.
Mathematics
1 answer:
miss Akunina [59]3 years ago
4 0

Answer:

5,000

Step-by-step explanation:

x× 5 %=250

x=250×100÷5=5000

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 Neda sells televisions. She earns a fixed amount for each television and an additional $ 15 if the buyer gets an extended warra
Alex Ar [27]

Answer:

$50

Step-by-step explanation:

15x18=270

1170-270=900

900/18=50

7 0
3 years ago
Which one would make me more money?
disa [49]

Answer:

im gouing to use 3 hours as an example so the first hour is 5 dollars and 8 dollars for each additional hour there are 2 additional hours which would be 16 dollars from the additional hours and plus 5 dollars from the first hour so 21 dollars

and the other option like i said earlier 3 hours is the example so 6*2 becasue their are 2 additional hours which is 12 plus 15 dollars from the first hour so 27 dollars

so the answer would be charge 15 dollars for the first hour and 6 for additional hour

can i get brainly please

3 0
3 years ago
Ten plus 6 times a number n is equal to 5 less<br> than the number n.
Gala2k [10]

Answer:

Step-by-step explanation:

10+6n=n-5

6n-n=-5-10

5n=-15

n=-3

7 0
4 years ago
] It is claimed that 42% of US college graduates had a mentor in college. For a sample of college graduates in Colorado, it was
Bad White [126]

Answer:

z=\frac{0.480 -0.42}{\sqrt{\frac{0.42(1-0.42)}{1045}}}=3.930  

The p value for this case would be given by:

p_v =P(z>3.930)=0.0000443  

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis so then we can conclude that the true proportion is significantly higher than 0.42

Step-by-step explanation:

Information given

n=1045 represent the random sample selected

X=502 represent the college graduates with a mentor

\hat p=\frac{502}{1045}=0.480 estimated proportion of college graduates with a mentor

p_o=0.42 is the value that we want to test

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true proportion is higher than 0.42, the system of hypothesis are.:  

Null hypothesis:p \leq 0.42  

Alternative hypothesis:p > 0.42  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info we got:

z=\frac{0.480 -0.42}{\sqrt{\frac{0.42(1-0.42)}{1045}}}=3.930  

The p value for this case would be given by:

p_v =P(z>3.930)=0.0000443  

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis so then we can conclude that the true proportion is significantly higher than 0.42

7 0
3 years ago
HELP PLEASE!!!
Hitman42 [59]

Answer:

1. false

2. 17 times

Step-by-step explanation:

The sum of all the probabilities of outcomes of an event is equal to 1

2.  A die has  1,2,3,4,5,6

P(4) = number of 4's/ total numbers

       = 1/6

Multiply the number of roll's by the probability of getting a 4

100 *1/6 = 50/3 = 16 2/3

This is approximately 17

3 0
4 years ago
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