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luda_lava [24]
3 years ago
13

Please help me with math

Mathematics
1 answer:
Anna [14]3 years ago
4 0

By observing the graph we can note down the following things about the boundary line:

  1. It has a positive slope.
  2. It cuts the X-axis at (5,0)
  3. It cuts the Y-axis at $(0,-x)$, where $|x|$ is some value less than 2 but greater than 1.

Let's look at the shaded region. The origin lies inside it.

Thus, the point $(0,0)$ satisfies the equation of the region.

Upon putting it in the options, we find that only two options: 2 and 4 satisfy the inequality $0<5$

Now find the Y-intercept of the boundary line:

Option 4) $0-2y=5$

$y=\frac{-5}{2}<-2$

Since it is smaller than -2, it is the wrong option.

Hence, correct option is $\boxed{x-3y<5}$

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John spent half of his weekly allowance
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$6

Step-by-step explanation:

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3 years ago
3+2 .4 - √(16 ) - 2 + 12 =
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3 years ago
How to find 62%of $400​
gayaneshka [121]

Answer:

248

Step-by-step explanation:

Solution for What is 400 percent of 62:

400 percent *62 =

(400:100)*62 =

(400*62):100 =

24800:100 = 248

Now we have: 400 percent of 62 = 248

Question: What is 400 percent of 62?

Percentage solution with steps:

Step 1: Our output value is 62.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$62=100\%.

Step 4: Similarly, x=400\%.

Step 5: This results in a pair of simple equations:

62=100\%(1).

x=400\%(2).

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

\frac{62}{x}=\frac{100\%}{400\%}

Step 7: Again, the reciprocal of both sides gives

\frac{x}{62}=\frac{400}{100}

\Rightarrow x=248

Therefore, 400 of 62 is 248

5 0
3 years ago
Read 2 more answers
Complete the pattern 274÷1=
Orlov [11]
The answer 274 because anything divided by one is itself
5 0
3 years ago
Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [
Darya [45]

Answer:

<em>A=3 and B=6</em>

Step-by-step explanation:

<u>Increasing and Decreasing Intervals of Functions</u>

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9

Computing the first derivative:

f' ( x ) = - 6 x^3 + 54 x - 108

We find the critical points equating f'(x) to zero

- 6 x^3 + 54 x - 108=0

Simplifying by -6

x^2 -9 x +18=0

We get the critical points

x=3,\ x=6

They define the following intervals

(-\infty,3),\ (3,6),\ (6,+\infty)

Thus A=3 and B=6

3 0
3 years ago
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