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2 answers:
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ST = 7.2
RT = 4.04
m∠S = 34°
Solution:
Given ΔRST is a right triangle.
RS = 6, ∠T = 56°
1.206 × 6 = ST
7.236 = ST
ST = 7.2
0.674 × 6 = RT
4.044 = RT
RT = 4.04
To find the measure of angle S.
Sum of the interior angles of the triangle = 180°
m∠R + m∠S + m∠T = 180°
90° + m∠S + 56° = 180°
m∠S + 146° = 180°
m∠S = 180° – 146°
m∠S = 34°
Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
sq. units.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to