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laiz [17]
3 years ago
7

Chester has less than $25 to spend at the county fair. The entrance fee is $5, and each ride costs $3. The number of rides, r, t

hat Chester can go on is represented by the inequality 3r + 5 < 25. Select the most amount of rides Chester can go on without overspending
Mathematics
1 answer:
padilas [110]3 years ago
4 0

Answer:

6 rides

Step-by-step explanation:

3r+5<25

3r<20

r<6.67

rides=6

check answer

3r+5<25

3(6)+5<25

18+5<25

23<25

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What is the missing reason in the proof?
IrinaVladis [17]

We can identify that the missing reason in the proof is: Definition of Congruent angles.

<h3>How to give proof of a congruent triangle?</h3>

We know that an angle measure of 90° of ∠ABC in the triangle means that it is a right angle triangle.

We also see that ∠ADB is also a right angle and is equal to 90°.

Now, since they have exactly the same measure, these angles are congruent. Then we can say that the angles are congruent and as such:

∠ABC ≅ ∠ABD

Thus, we can identify that the missing reason is: Definition of Congruent angles.

Read more about Triangle proof at; brainly.com/question/1248322

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3 0
2 years ago
(15 points please help)
dsp73
C. You can graph it on Desmos and all the given points work. 
5 0
3 years ago
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The probability that a rental car will be stolen is. 4. if 3500 cars are rented, what is the approximate poisson probability tha
kozerog [31]

Using the Poisson distribution, there is a 0.8335 = 83.35% probability that 2 or fewer will be stolen.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

The parameters are:

  • x is the number of successes
  • e = 2.71828 is the Euler number
  • \mu is the mean in the given interval.

The probability that a rental car will be stolen is 0.0004, hence, for 3500 cars, the mean is:

\mu = 3500 \times 0.0004 = 1.4

The probability that 2 or fewer cars will be stolen is:

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-1.4}1.4^{0}}{(0)!} = 0.2466

P(X = 1) = \frac{e^{-1.4}1.4^{1}}{(1)!} = 0.3452

P(X = 2) = \frac{e^{-1.4}1.4^{2}}{(2)!} = 0.2417

Then:

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2466 + 0.3452 + 0.2417 = 0.8335

0.8335 = 83.35% probability that 2 or fewer will be stolen.

More can be learned about the Poisson distribution at brainly.com/question/13971530

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4 0
1 year ago
A class of 32 students contains 15 boys.
LiRa [457]

Answer:

11 boys walk to school each day

Step-by-step explanation:

<em>*The following will be assumed: the only genders of students in the class are male or female; the only options for getting to school are walking or not walking</em>

If there are 32 students in the class total, and there are 15 boys,

32 - 15 = 17

there are 17 girls.

If 8 of these girls do not walk to school,

17 - 8 = 9

9 girls walk to school

So, if 20 total students walk to school, and 9 of those are girls

20 - 9 = 11

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3 0
2 years ago
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-3 is a solution of y &gt; -2<br> true or false
BartSMP [9]
That is false.  When you look at a number line, -3 is to the left of -2.  A number to the left of another number is less than the number to the right. 
5 0
3 years ago
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