9514 1404 393
Answer:
- √51 ≈ 7.141
- 1313/9900 ≈ 0.133
- ∛971 ≈ 9.902
Step-by-step explanation:
The usual rules of rounding apply. If the digit in the 4th decimal place is 5 or more, then 1 is added in the 3rd decimal place. The roots are found using your calculator. The first 4 digits of the repeating decimal are clearly visible already.
a) √51 ≈ 7.141428... ≈ 7.141
b) 0.1326_26 ≈ 0.133
c) ∛971 ≈ 9.90238... ≈ 9.902
_____
<em>Additional comment</em>
The repeating decimal is equivalent to the fraction 1313/9900.
<span>19/20 is a bigger fraction.</span>
Its six idk really ask your teacher for more help
P would equal negative three.
If <em>a</em> is fixed and <em>b</em>,<em>c</em> are unknowns then the equation <em>b</em>+<em>c</em>=10-<em>a</em> has 11-<em>a</em> solutions. They are pairs (b,c): (0,10-a), (1,9-a), (2,8-a), ... (10-a,0). As <em>a</em> runs from 0 to 10 we have total number of solutions (11-0)+(11-1)+...(11-1)=11+10+...+1=(1+11)*11/2=66.
