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Klio2033 [76]
3 years ago
6

What is the area of the triangle below? 8 in. 17 in.

Mathematics
2 answers:
zmey [24]3 years ago
6 0

Answer:

68

Step-by-step explanation:

almond37 [142]3 years ago
5 0

Answer:

68 In

8*17- now, this would give you the area of a rectangle or square. but, since this is half of a rectangle or square, you divide that answer in half, giving you your final answer of 68 square inches as the area

Step-by-step explanation:

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Solve for v.<br> -8v+3(v-3) = 16
puteri [66]

Hi there! :)

Answer:

\huge\boxed{v = -5}

-8v + 3(v - 3) = 16

Distribute the 3:

-8v + 3(v) + 3(-3) = 16

-8v + 3v - 9 = 16

Combine like terms and simplify:

-5v - 9 = 16

-5v - 9 + 9 = 16 + 9

-5v = 25

Divide both sides by -5:

-5v/(-5) = 25/(-5)

v = -5.

7 0
3 years ago
Read 2 more answers
Is the relationship linear, exponential, or neither?
kati45 [8]

Answer:

Neither linear nor exponential

Step-by-step explanation:

To check for a linear relationship.  Find slope.

slope=  (-1  -  (-2)) / ( 5 - 2)  = 1/3

check  other points

slope = (1 - (-1) )/ (8 - 5) =  2/3

check more

slope = (4 - 1) / (11 - 8) = 3/ 3 = 1

Nope.

try assuming an exponential:

y = c * (a^x)

-2 =  c* (a^2);    -2/c = a^2

-1 = c *(a ^5);    -1/c = a^5

1 =  c * (a^8),     1/c = a^8

(-2/c)^4 = a^8 = 1/c

16/(c^4) = 1/c

c^3 = 16,  then    a = root (-2/ cube-root(16) )

The change from negative to postive  would not work  for y = c(a^x)

so...

assume   y =  a^x  + k

-2 = a^2  + k

-1 = a^5  + k

...  I would say neither..

6 0
3 years ago
Can someone help me with my homework please?
grigory [225]
Multiplying x^2 by 5 stretches the graph vertically by a factor of 5.  Try graphing both x^2 and 5x^2 and see for yourself that this is correct.
3 0
4 years ago
A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated
zysi [14]
Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)
8 0
3 years ago
Solve the system of equations 4x+5y=-1 and -5x-8y=10 by combining the equations.
Nimfa-mama [501]

The solution of the equation are as follows:

x = 6 and y = -5

<h3 />

<h3>How to solve the system of equation?</h3>

4x + 5y = -1

-5x - 8y = 10

Therefore,

20x + 25y = -5

-20x - 32y = 40

-7y = 35

y = -5

Hence,

4x + 5(-5) = -1

4x - 25 = -1

4x = -1 + 25

4x = 24

x = 24 / 4

x = 6

learn more on equation here:brainly.com/question/14383993

#SPJ1

6 0
2 years ago
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