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scoundrel [369]
3 years ago
6

5

Mathematics
1 answer:
rodikova [14]3 years ago
8 0

Answer:

D

Step-by-step explanation:

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Bumek [7]
So go down and up then look it up on the web so you can look good in it that really helps
7 0
2 years ago
Find the total area for the regular pyramid.
hram777 [196]

Answer:

  • Option B

Step-by-step explanation:

Given is the hexagonal pyramid.

We know the radius of the base is same as its side.

<u>Find the base area:</u>

  • A = 3√3/2a²
  • A = 3√3/2*6² = 54√3

<u>Given the height and radius, find the side of the lateral triangular faces:</u>

  • \sqrt{8^2+6^2} =\sqrt{100} =10

Each of 6 triangles have sides 10, 10 and 6 units.

<u>Find the area using heron's formula:</u>

  • s = P/2 = (10*2 + 6)/2 = 13
  • s - a = s - b = 13 - 10 = 3
  • s - c = 13 - 6 = 7
  • A = \sqrt{s(s-a)(s-b)(s-c)} =\sqrt{13*3*3*7} =3\sqrt{91}

<u>Total surface area:</u>

  • S = 6*3\sqrt{91}+54\sqrt{3}  =18\sqrt{91}+54\sqrt{3}

Correct choice is B

3 0
2 years ago
What is the vale of ■ in this equation?<br>7×9=(7×10)-(7×■)
aliina [53]
The answer is 1 because 7*9 is 63
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5 0
3 years ago
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Please help me with this question, thanks.
arlik [135]

Answer:

  2.48×10^13 miles

Step-by-step explanation:

There are about (365.25 days)(86400 seconds/day) = 31,557,600 seconds in one year. There are 1609.344 meters in one mile. So, the conversion can be written as ...

  (4.22 ly) (3×10^8 m/s) (3.15576×10^7 s/yr) / (1.609344×10^3 m/mi)

  = 4.22×3×3.15576/1.609344×10^(8+7-3) mi

  ≈ 24.8×10^12 mi

4.22 light years is about 2.48×10^13 miles

8 0
3 years ago
What is the best estimate for the value of the expression? (StartFraction 34 over 8 EndFraction minus StartFraction 16 over 3 En
marusya05 [52]

Answer:

-2  1/2

Explanation :

took the test on ed

7 0
3 years ago
Read 2 more answers
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