Find the area of the following shape. You must show all work to receive credit.

Mathematics

1 answer:

Svetach [21]2 years ago

8 0

Answer:

Step-by-step explanation:

Split up the shape into three smaller shapes: a triangle at the top, a 1 by 2 rectangle, and a triangle at the bottom left. The 1 by 2 rectangle has an area of 2. The triangle at the top has an area of (4*2)/2 = 4, and the triangle at the bottom right has an area of (2*2)/2 = 2.

Therefore, the total area of the shape is 2 + 4 + 2 = 8

Hope this helped!

<em>Please mark as brainliest!!!</em>

You might be interested in

Celine is estimating the number of tiles in a mosaic. There are 7 different colors, and 472 tiles of each color. There are also

ValentinkaMS [17]

Answer:

3,400 tiles

Step-by-step explanation:

Since there is 472 tiles of each 7 colors,

Multiply 472 by 7 to get 3,304

Then you would add the 96 blank tiles to get exactly

3.400 tiles.

8 0

4 years ago

A circle has a diameter of 16 m. What is its circumference

Sav [38]

The answer should be 50.24 m

5 0

2 years ago

Help me wit dis pleasee??

elixir [45]

A straight line is 180 degrees. To get x, you subtract 117 from 180.

180-117 is 63.

x= 63.

x+y is 90 degrees so to find y, you subtract x from 90.

90-63 is 26.

y=27.

4 0

3 years ago

FIRST TO ANSWER GETS BRAINLIEST!

scZoUnD [109]

Answer:

$\huge \boxed{ \red{ \boxed{c)78 \: units ^{2} }}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

circle
PEMDAS

<h3>tips and formulas:</h3>

$\rm \:A_{shaded}= \dfrac{\theta}{360} \times \pi {r}^{2}$

<h3>let's solve:</h3>

$\sf sustitute \: the \: value \: of \: \theta \: and \: r : \\ A_{shaded} = \frac{140}{360} \times \pi \times {8}^{2}$
$\sf simpify \: squre : \\ A_{shaded} = \frac{140}{360} \times \pi \times 64$
$\sf simpify \: fraction: \\ A_{shaded} = \frac{7}{18} \times \pi \times 64$
$\sf reduce \: 64: \\ A_{shaded} = \frac{7}{ \cancel{ \: 18} \: ^{9} } \times \pi \times \cancel{ 64} \: ^{32} \\ A_{shaded} = \frac{7}{9} \times \pi \times 32\\ A_{shaded} = \frac{224\pi}{9}$